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Oksanka [162]
2 years ago
8

Which equation shows a correct relation for triangle RSQ?

Mathematics
1 answer:
son4ous [18]2 years ago
4 0

Answer:

sinQ=cosR

Step-by-step explanation:

First we need to find out the measure of ∠R.

The sum of all the angles in a triangle add up to 180. Therefore:

∠Q+∠R+∠S=180

66+∠R+90=180

∠R=180-156

∠R=24°

Since ∠Q≠∠R, sinQ≠sinR. So the first option is incorrect - let's try the second one.

sinQ=cosR

sin66=cos24

0.9135454576=0.9135454576

So the second equation is the correct relation.

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<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

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