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wariber [46]
2 years ago
8

Put the equation y =x^2-8x + 12 into the form y(x-h)^2+k Answer: y =

Mathematics
1 answer:
zlopas [31]2 years ago
7 0

Answer:

<em>y = (x - 4)² - 4 </em>

Step-by-step explanation:

y = x² - 8x + 12

y = ( x² - 2(4)x + 4² ) - 4² + 12

<em>y = (x - 4)² - 4</em>

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PLEASE HELP<br> NO LINKS
bezimeni [28]

Answer:

The first blank is $640.30

The second blank is 670

Step-by-step explanation:

6 0
3 years ago
Solve for the indicated variable.<br><br> y = mx + b for x<br><br> x=
kogti [31]

Answer:

y-b/m = x

Step-by-step explanation:

y = mx + b

~Subtract b to both sides

y - b = mx

~Divide m to both sides

y-b/m = x

Best of Luck!

3 0
3 years ago
Solve all of them please u get 30 points​
nika2105 [10]

Step-by-step explanation:

from which text book please

8 0
2 years ago
Read 2 more answers
Hi, can someone please help, and possibly explain the answer please.
mr_godi [17]

Answer:

x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

Step-by-step explanation:

Quadratic formula: x=\frac{-b\±\sqrt{b^2-4ac} }{2a} when the equation is 0=ax^2+bx+c

The given equation is 1=-2x+3x^2+1. Let's first arrange this so its format looks like y=ax^2+bx+c:

1=-2x+3x^2+1

1=3x^2-2x+1

Subtract 1 from both sides of the equation

1-1=3x^2-2x+1-1\\0=3x^2-2x+0

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

I hope this helps!  

8 0
2 years ago
Solve the equation for the indicated variable S=2πrh+2πr²<br> Solve for h
valina [46]

Answer:

Good luck :)

Step-by-step explanation:

S=2πrh+2πr ²

subtract 2πr ² from each side

S -2πr ² = 2πrh

divide by 2πr from each side

(S -2πr ² )/ 2πr  = h

4 0
3 years ago
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