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3 years ago

How many Erving of 3/4 cup of beans are in half a cup?

Mathematics

1 answer:

jenyasd209 [6]3 years ago

7 0

Well a half cup is 2/4 and if the serving size is 3/4 there is only 66.66% of the serving size needed hope this helps!

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Juliet has a choice between receiving a monthly salary of $1750 from a company or a base salary of $1600 and a 3% commission on

Westkost [7]

For an amount of sales of $5,000, the two salary choice will be equal

Let the amount of sales be $x

The 3% she will receive will be;

$\frac{3}{100}\times x\text{ = 0.03x}$

We add this to the base salary and equate to the former monthy salary

We have this as;

$\begin{gathered} 1750\text{ =1600 + 0.03x} \\ 1750-1600\text{ = 0.03x} \\ 150\text{ = 0.03x} \\ x\text{ = }\frac{150}{0.03} \\ x\text{ = \$5000} \end{gathered}$

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1 year ago

Which best explains why state governments are better able to focus on the needs of their citizens than the federal

sesenic [268]

Answer:

The state governments are able to focus entirely on the citizens that live there. The federal government has to deal with wide spread, national issues, and would not provide the care and attention that the smaller state governments can.

Step-by-step explanation:

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3 years ago

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tangare [24]

Answer:

(3+3) x (3+1)

Step-by-step explanation:

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2 years ago

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Write 0.27 as a fraction

aniked [119]

The answer is: 27/100

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3 years ago

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A store finds that its sales revenue changes at a rate given by S'(t) = −30t2 + 420t dollars per day where t is the number of da

allochka39001 [22]

Answer:

Step-by-step explanation:

Give the rate of change of sales revenue of a store modeled by the equation $S'(t)= -30t^{2} + 420t$ . The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

$\int\limits {S'(t)} \, dt = \int\limits ({-30t^{2}+420t }) \, dt \\S(t) = \frac{-30t^{3} }{3}+\frac{420t^{2} }{2}\\ S(t)= -10t^{3} +210t^{2} \\$

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;

$Given\ S(t) = -10t^{3} + 210t^{2}$

$S(0) = -10(0)^{3} + 210(0)^{2}\\S(0) = 0\\S(7) = -10(7)^{3} + 210(7)^{2}\\S(7) = -3430+10,290\\S(7) = 6,860$

Total sales = S(7) - S(0)

= 6,860 - 0

Total sales for the first week = $6,860

b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;

Total sales for the second week = S(14)-S(7)

Given S(7) = 6,860

To get S(14);

$S(14) = -10(14)^{3} + 210(14)^{2}\\S(14) = -27,440+41,160\\S(14) = 13,720$

The total sales for the second week after campaign ends = 13,720 - 6,860

= $6,860

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3 years ago