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3 years ago

A standard coffe mug has a capacity

Mathematics

1 answer:

Norma-Jean [14]3 years ago

5 0

$26 * 16 = 416$

1 quart = 32 ounces

$\frac{416}{32} =13$

She will need 13 quarts of coffee.

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1/2 divided by 3/4 = 1/a times b/c = d/e

Vinvika [58]

Step-by-step explanation:

1/2 ÷ 3/4 = 1/2 × 4/3 = 4/6

a = 2

b = 4

c = 3

d = 4

e = 6

6 0

3 years ago

the Children's Hospital sponsors a 10k race to raise money. it receives $75 per race entry and $10,000 in donations but it must

masha68 [24]

Answer:

There would need to be at least 1,800 entries in order for them to meet their goal.

Step-by-step explanation:

To find this, we must write an equation that helps solve it. We know that for every entry (x), we gain 75 and lose 25. We can express this as the following.

75x - 25x

Then we can add the number of donations.

75x - 25x + 10,000

Then we can set it as greater than or equal to the goal number.

75x - 25x + 10,000 ≥ 100,000

Now we solve this using the order of operations.

75x - 25x + 10,000 ≥ 100,000 ----> Combine like terms

50x + 10,000 ≥ 100,000 ------> Subtract 10,000

50x ≥ 90,000 -----> Divide by 50

x ≥ 1,800

4 0

3 years ago

Read 2 more answers

Pls helpppppppppppppo

vovikov84 [41]

Answer:

b I do believe

Step-by-step explanation:

can you help me

8 0

3 years ago

What are three expressions equivalent to : 2g+10h?. <br> PLEASE!!!!!

stellarik [79]

Answer:

2(1g + 5h)

(2 x g) + (2 x 5h)

4g + 10h

_______

I don't know the options so I just did 3 possible ways it could be equal

8 0

3 years ago

HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH

8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

$4+\sqrt{6x}$

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

$4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}$

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

$\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}$

Thank you

8 0

3 years ago