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Olegator [25]
2 years ago
8

Graph the line with slope 3 passing through the point (4,-5)

Mathematics
1 answer:
Rasek [7]2 years ago
8 0

Answer:

here you go (I can not draw a straight line)

Step-by-step explanation:

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Complete the equation of the line through (3, -8) and (6,-4).<br> Use exact numbers.
Lina20 [59]

Answer:

y = 4/3x - 12

Step-by-step explanation:

To find the slope of the line, we do (y2 - y1) / (x2 - x1)

If we put in the values, we'll get

(-4 - -8) / (6 - 3)

Simplify and get

(-4 + 8) / 3

4 / 3

Your slope is now 4/3, so you can put it into your equation y = mx + b

y = 4/3x + b

To find b, we can plug in the values from one of your points. Lets use (3, -8)

-8 = 4/3 * 3 + b

Now solve the equation

-8 = 4 + b

-12 = b

Now that you have b, your equation is complete:

y = 4/3x - 12

4 0
3 years ago
A study of king penguins looked for a relationship between how deep the penguins dive to seek food and how long they stay underw
Serggg [28]

Answer:

b = 0.0138

Step-by-step explanation:

Given

Regression Equation:

DD=2.69+0.0138D

Required

Determine the slope of the regression line

The equation of regression is of the form

Y =  a + bX

Where b represents the slope;

Compare Y =  a + bX to the given equation

DD=2.69+0.0138D

We have that:

Y = DD

a = 2.69

b = 0.0138

X = D

Hence; the slope is:

b = 0.0138

7 0
3 years ago
If every student in a large Statistics class selects peanut M&amp;M’s at random until they get a red candy, on average how many
kotykmax [81]

Question:

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select peanut M&M's from an extra-large bag looking for a red candy.

If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many M&M’s will the students need to select? (Round your answer to two decimal places.).

Answer:

If every student in the large Statistics class selects peanut M&M’s at random until they get a red candy the expected value of the number of  M&M’s the students need to select is 8.33 M&M's.

Step-by-step explanation:

To solve the question, we note that the statistical data presents a geometric mean. That is the probability of success is of the form.

The amount of repeated Bernoulli trials required before n eventual success outcome or

The probability of having a given number of failures before the first success is recorded.

In geometric distribution, the probability of having an eventual successful outcome depends on the the completion of a certain number of attempts with each having the same probability of success.

If the probability of each of the preceding trials is p and the kth trial is the  first successful trial, then the probability of having k is given by

Pr(X=k) = (1-p)^{k-1}p  

The number of expected independent trials to arrive at the first success for a variable Xis 1/p where p is the expected success of each trial hence p is the probability for the red and the expected value of the number of trials is 1/p or where p = 12 % which is 0.12

1/p = 1/0.12 or 25/3 or 8.33.

4 0
3 years ago
What is the value of the constant in the expression?<br> 2x2 + 3x - y - 18 + 7y2
Virty [35]
I think it’s 3x

Hope it helps
8 0
3 years ago
Evaluate 5x when x =8
andrey2020 [161]

Answer:

:( help me on my question

Step-by-step explanation:

4 0
3 years ago
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