All categories

3 years ago

What is the simplest form of 13/14

Mathematics

2 answers:

OleMash [197]3 years ago

7 0

13/14 is already in simplest form because they have no common factors.

sergeinik [125]3 years ago

4 0

This is already in it's most simple form because it cannot be divide further.

You might be interested in

Find slope of a straight line if both intercept are equal

Juli2301 [7.4K]

Answer:

-1

Step-by-step explanation:

Let the points be (0, a) and (a, 0) (As it mentions the intercepts are equal)

==============================================================

Applying slope formula :

⇒ m = 0 - a / a - 0

⇒ m = -a/a

⇒ m = -1

6 0

1 year ago

Factor each completely. 2x3 - 9x2 + 9x

EleoNora [17]

Answer:

x(2x−3)(x−3)

Step-by-step explanation:

2x^3−9x^2+9x

= x(2x−3)(x−3)

4 0

2 years ago

What is the value of C in the matrix equation below?

lara [203]

Given:

The matrix equation is:

$\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}$

To find:

The value of matrix C.

Solution:

Let $A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}$ . Then the given equation can be rewritten as

$A-C=B$

$-C=B-A$

$C=-(B-A)$

$C=A-B$

On substituting the values of the matrices, we get

$C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}$

$C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}$

$C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}$

$C=\begin{bmatrix}-4&2&-7\end{bmatrix}$

Therefore, the correct option is C.

6 0

2 years ago

Read 2 more answers

Please help!!!

Leto [7]

Answer:

- The scientist can use these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

- The scientist can substitute these measurements into $cos\alpha=\frac{adjacent}{hypotenuse}$ and solve for the distance between the Sun and the shooting star (which would be the hypotenuse of the righ triangle).

Step-by-step explanation:

You can observe in the figure attached that "AC" is the distance between the Sun and the shooting star.

Knowing the distance between the Earth and the Sun "y" and the angle x°, the scientist can use only these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

This is:

$cos\alpha=\frac{adjacent}{hypotenuse}$

In this case:

$\alpha=x\°\\\\adjacent=BC=y\\\\hypotenuse=AC$

Therefore, the scientist can substitute these measurements into $cos\alpha=\frac{adjacent}{hypotenuse}$ , and solve for the distance between the Sun and the shooting star "AC":

$cos(x\°)=\frac{y}{AC}$