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Veronika [31]
3 years ago
6

Find a formula for the general term an of the sequence, assuming that the pattern of the first few terms continues. (Assume that

n begins with 1.) 1, − 1/ 3 , 1 /9 , − 1 /27 , 1 /81 , . . .
Mathematics
1 answer:
lions [1.4K]3 years ago
7 0

9514 1404 393

Answer:

  a[n] = (-1/3)^(n -1)

Step-by-step explanation:

The terms have a common ratio of (-1/3)/(1) = -1/3. The general term for a geometric sequence with first term a1 and common ratio r is ...

  a[n] = a[1]×r^(n-1)

Here, a[1] = 1, so this is ...

  a[n] = (-1/3)^(n-1)

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If a = (3-2√2) find the value of a4+ 1/a4 ​
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Answer:

  1154

Step-by-step explanation:

Perhaps the easiest way to evaluate this numerical expression is to let a calculator do it. Alternatively, we can compute the value from a +1/a.

__

<h3>expression</h3>

Consider the square of a +1/a:

  (a +1/a)^2 = a^2 +2(a)(1/a) +1/a^2 = (a^2 +1/a^2) +2

This means ...

  a^2 +1/a^2 = (a +1/a)^2 -2

Similarly, using a^2 for 'a' in the above, we have ...

  a^4 +1/a^4 = (a^2 +1/a^2)^2 -2

<h3>numerical value</h3>

The value of a +1/a is ...

  a+\dfrac{1}{a}=3-2\sqrt{2}+\dfrac{1}{3-2\sqrt{2}}=(3-2\sqrt{2})+\dfrac{3+2\sqrt{2}}{3^2-(2\sqrt{2})^2}\\\\=(3-2\sqrt{2})+(3+2\sqrt{2})\\\\a+\dfrac{1}{a}=6

Then the value of a^2 +1/a^2 is 6^2 -2 = 34

and the value of a^4 +1/a^4 is 34^2 -2 = 1154

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Answer:

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Step-by-step explanation:

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