Answer:
Step-by-step explanation:
Given that Prof Liu gave the same quiz to the students in her morning class and in her afternoon class. the average score for the two classes combined was 84.
(1) The average score for the students in the morning class was 80
(2) the average score for the students in the afternoon class was 86
Let m be the no of students in I class and n in II class
Total of I class = 80m and
Total of II class = 86n
Total of both classes = 80m +86n
Average =
m cannot be equal to n because in that case average would have been 83
If m >n, then say n =m+a
then average = 
Because 86 is more times added, average score would decrease hence we would not get 84.
So I class is getting less score of 80 to get a score average of more than 83 (the average) the class II should have more students.
The answer to this word problem is letter A. 200.
Here is the solution:
given:
candy bars in batches of 800
fixed cost of $ 20 per batch
variable cost of $ 0.10 x
x= the number of batches
<u>$ 20 ( 800 )</u> = <u>16, 000</u>
$ 0.10 (800) 80
= 200
Answer:
x^(1/3)
Step-by-step explanation:
let's start with x^2 / x^(2/3), then we'll move on the the 4th root
when dividing exponents with the same base, we subtract the exponents:
x^2 / x^(2/3) = x^(2 - 2/3) = x^(4/3)
the fourth root of x^4/3 can become x^(4/3 * 1/4)
(i used the formula x^(m/n) = nth root of x^m)
x^(4/3 * 1/4) = x^1/3
hope this helps! <3
Answer:
10 with a remainder of 1
Step-by-step explanation:
and also, you should use a program like cymath for that. Only use brainly for problems that cant be answered by a website like that.
Good luck!