Calculate the size of one interior angle of a regular polygon with 40 sides.
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Answer:
I hope this will help you
Step-by-step explanation:
f(x) = 2x²+8x+10
vertex point :
x = -8/2(2)= -8/4
=> x = -2 <= this is a symetry axis
f(-2)= 2(-2)²+8(-2)+10=8-16+10=2
the vertex point : (-2, 2)
intercept with y-axis :
f(0) = 0+0+10 = 10
the point : (0, 10)
the drawing as attached
First getting x as a numerator rather than a denominator. Then grouping like terms by moving 5 from the left side to the right. Work below:
