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ella [17]
4 years ago
10

How to algebraically find the limit of a function as x approaches infinity?

Mathematics
1 answer:
Sauron [17]4 years ago
5 0

Well... One way you can do this is by testing a set of arrays and see the trend. If I chose to find what y1 is in (100, y1) and what y2 is in (101, y2), I would find the difference between y2 and y1. If y2 - y1 is positive, this means there is a positive relationship and y is also approaching POSITIVE infinity. A negative relation means that it is approaching NEGATIVE infinity. However, it could be approaching a single number like "4" for instance, and you just need to plug in the right number of data sets to make that educated guess.

Formula Example:
5 + 1 / (x + 1) will always approach 5 because "1 / (x + 1) will approach 0".

Hope this helps.

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Therefore, the only statement that is equivalent to <em>"the </em><em>price decreased</em><em> by </em>\frac{1}{3}<em>"</em> is:

<u>F. The price is now </u><u>66, 2/3% </u><u>of what it was before</u>

<u />

<u />

Given that the original price of something decreased by 1/3, it means:

the original price is reduced by one-third.

  • One-third is not equal to half of the price.

  • 1/3 is less than 1/2.

  • 1/3 of the original price would be \frac{1}{3} \times 100 = 33.3% less of the original price.

  • This means that the new price would be: <em><u>100 - 33 = 66% of the </u></em><em><u>original price.</u></em> This shows a reduction in price. The price would drop.

  • 1/3 is more than a quarter (1/4).

<em>Any option showing or suggesting an increase is definitely the wrong answer.</em>

Therefore, the only statement that is equivalent to <em>"the </em><em>price decreased</em><em> by </em>\frac{1}{3}<em>" </em>are:

<u><em>F. The price is now </em></u><u><em>66, 2/3% </em></u><u><em>of what it was before</em></u>

Learn more here:

brainly.com/question/11293133

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