Over which part of the domain is the piecewise function defined as f(x) = 0.05x – 300?
2 answers:
You might be interested in
First, lets create a equation for our situation. Let 
be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>
<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:
. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)
We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
</span>
<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:
We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Answer:
correct option is d. $242.81
Step-by-step explanation:
given data
APR = 25.5% = = 2.125
paid = $3,729
solution
we get here finance charge on the 1st month by multiplying 3,729 and now adding it to existing balance
so we get finance charge for the second and third months similarly as
APR ÷ 100 = = 0.02125
so 1st
= $3,729 × 0.02125
= 79.25
and
$3,729 + $79.25 = $3808.24
so for next
= $3808.24 × 0.02125
= 80.93
and
$3808.24 + $80.93 = $3889.17
so for next
= $3889.17 × 0.02125
= 82.64
and
$3889.17 + $ 82.64 = $3971.81
so
finance charge = 3971.81 - 3729
finance charge = 242.81
so correct option is d. $242.81