Cos(θ) = -20/√((-20)^2 +(-21)^2)
.. = -20/-√841 . . . . . . . . . . . . . . . . . θ is a 4th-quadrant angle, so cos(θ) > 0
.. = 20/29

The value of the cosine is 20/29.

3 0

3 years ago

Read 2 more answers

Which of the following points is in the solution set of y>-x² + 5?

eimsori [14]

Uh I did not learn this yet but I think The answer is 2,4

7 0

2 years ago

Find the length of side x I simplest radical form

alekssr [168]

Answer:

Option A

Step-by-step explanation:

By applying Pythagoras theorem in ΔABC,

(Hypotenuse)² = (Leg 1)² + (Leg 2)²

AC² = AB² + BC²

AC² = 6² + 5²

AC = $\sqrt{61}$

Similarly, by applying Pythagoras theorem in ΔACD,

AD² = AC² + CD²

(10)² = $(\sqrt{61})^2$ + x²

x² = 100- 61

x² = 39

x = √(39)

Option A will be the answer.

7 0

2 years ago