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labwork [276]
3 years ago
12

Mathematicians use "..." to mean that a pattern continues: it

Mathematics
1 answer:
Fofino [41]3 years ago
6 0

Answer:

Step-by-step explanation:

We khow that A is the sum of all odd numbers that are less than 100

So A= 1+3+5+...+99

We can calculate this sum without adding all this numbers one by one

A = the number of terms *( first term + last one ) over 2

To get the number of terms we substract the first term from the last term then we add one

We khow that odd numbers are wiritten this way : 2*n +1 where n is an integer

So 99= 2*49+1

1= 2*0+1

So the number of terms is : 49-0+1 =50

So A= 50*(1+99)/2 = 2500

Foloowing the same method we get :

B= (49-1+1)*(2+98)/2= 2450

A>B

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Y=-2/3x+2, y=3/2x+8 these lines are <br> A) parallel<br> B)perpendicular<br> C)neither
OLga [1]

Answer:

B) perpendicular

Step-by-step explanation:

i graphed them

7 0
3 years ago
Greatest common factors<br><br> 4,8<br> Can u do a factor tree I need help with it
solong [7]
4. 8
/ \ / \
2 x 2. 4 x 2
/ \
2 x 2

4: 2x2
8: 2x2x2

The GCF is 4

7 0
4 years ago
The box plot below represents some data set. What is the value of the median?
OLEGan [10]

Answer:

80

Step-by-step explanation:

Look at the box plot and look at each line.

The first line that is all the way to the left, that is the Quartile 1.

The last line all the way to the right, that is Quartile 3.

Now lets look at the box part.

The beggining of the box is the minimum.

The ending of the box is the maximum.

The middle line is the median.

How I remember it is Median=Middle

Hopw this hels :D

8 0
2 years ago
Factoring expressions 9+36w
alexdok [17]

Answer:

9( 1 + 4w)

Step-by-step explanation:

So if you're simplifying then you need to find the greatest common factor. The GCF is 9.

8 0
3 years ago
Julie will build a rectangular pen for her dog against a barn. A wall from the barn will form one side of the pen. She has 32 m
MAXImum [283]

Answer:

<h3> The width (side perpedicular to the barn):  <u>x = 8 m</u></h3><h3>      The lenght (side parallel to the barn):  <u>y = 16 m</u> </h3>

Step-by-step explanation:

x  - the width of the barn

She has 32 m of fencing so for the lenght remain (32-2x) m of fencing:

y = 32 - 2x

Area of the fencing:  A = x•y

A(x) = x•(32 - 2x)

A(x) = -2x² + 32x             ←  quadratic function

The maximum value of quadratic function occurs at:  x=-\frac b{2a}

a = -2,  b = 32

x=-\frac b{2a}=-\frac{32}{2\cdot(-2)}=-(-8)=8

32-2x = 32 - 2•8 = 16

4 0
3 years ago
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