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3 years ago

How many times does 80 go into 766 i need it asap

Mathematics

2 answers:

ra1l [238]3 years ago

6 0

Answer:

Step-by-step explanation:

puteri [66]3 years ago

4 0

Answer:

Step-by-step explanation:

the answer is 9.575

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Solve for x please. :)

solmaris [256]

Answer:

180-130=50

Step-by-step explanation:

done hope you like it

i use the 180 because its a straight line from the x to the 130

6 0

3 years ago

Helppp ill mark brainliest <br> look at the picture

Dominik [7]

Answer:

She will have to earn $3,100

Step-by-step explanation:

6,600-3,500=3,100

8 0

3 years ago

Read 2 more answers

Which of the following is not an equation

kompoz [17]

X - 4 is not an equation because it does not have an equal sign.

8 0

4 years ago

Find the length of BC.

nikklg [1K]

Answer:

Step-by-step explanation:

If the perimeter is 58,

take 17(2) for booth sides.

Which you will get 34.

58-34=24

Now you know that the remainder is the two vertical sides.

24/2=12

BC=12

5 0

3 years ago

Determine whether f(x) =3x^2+9x-2 has a maximum of a minimum value and find that value by hand.

xenn [34]

f(x) =3x^2+9x-2 has a minimum value. Minimum value of f(x) is $\frac{-35}{4}$

<u>Solution:</u>

Given, equation is $f(x)=3 x^{2}+9 x-2$

We have to find whether given equation has maximum or minimum for the given equation.

Now, we know that, f(x) is a quadratic equation and coefficient has $x^2$ is positive, then its graph is upward parabola. Which means that it will have minimum

The minimum value upward parabola will be its vertex.

So, let us convert f(x) into general form. That is,

$f(x)=a(x-h)^{2}+k$

where a is constant and (h, k) is vertex

$\text { Now }_{,} f(x)=3 x^{2}+9 x-2$

$\text { Adding and subtracting } \frac{27}{4} \text { for easier calculations }$

$f(x)=3 x^{2}+9 x+\frac{27}{4}-\frac{27}{4}-2$

Taking "3" as common from first three terms,

$f(x)=3\left(x^{2}+3 x+\frac{9}{4}\right)-\frac{27}{4}-2$

Now multiply and divide “2” with “3x” for easier calculations

$f(x)=3\left(x^{2}+2 \times \frac{3}{2} \times x+\left(\frac{3}{2}\right)^{2}\right)-\frac{27+2 \times 4}{4}$

$\begin{array}{l}{\text { By using }(a+b)^{2}=a^{2}+2 a b+b^{2}, \text { we get }} \\\\ {\left(x^{2}+2 \times \frac{3}{2} \times x+\left(\frac{3}{2}\right)^{2}\right)=\left(x+\frac{3}{2}\right)^{2}}\end{array}$

$f(x)=3\left(x+\frac{3}{2}\right)^{2}-\frac{35}{4}$

So, by comparison with general form we get,

$\mathrm{h}=-\frac{3}{2} \text { and } \mathrm{k}=\frac{-35}{4}$

$\text { Here, }(\mathrm{h}, \mathrm{k})=(\mathrm{x}, \mathrm{f}(\mathrm{x}))=\left(\frac{-3}{2}, \frac{-35}{4}\right)$

$\text { So, minimum value of } f(x) \text { is } \frac{-35}{4}$

5 0

3 years ago