Answer:
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Answer:
<h3>x = -3</h3>
Step-by-step explanation:
First let us get the equation of the coordinates
y-y0 = m(x-x0)
Using the coordinates ( - 3, 2 ), ( - 1, 0 )
m = 0-2/-1-(-3)
m = -2/2
m = -1
Substitute m = -1 and (-1, 0) into the formula
y - 0 = -1(x+1)
y = -x-1
f(x) = -x-1
Since f(x) = 2
2 = -x-1
-x = 2+1
-x = 3
x = -3
Hence the value of x is -3
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750
Correct answer is C)</span>
That is true but that’s not all units that are known for volume
Answer: She ran 0.25 laps a minute
Step-by-step explanation:
Every minute she runs 0.25 a minute which means that every 4 minutes she runs 1 lap which means if she run for 8 minutes she gets 2 laps
