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3 years ago

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!

Mathematics

1 answer:

slavikrds [6]3 years ago

3 0

Answer:

O A. 708.01

Step-by-step explanation:

Volume of a cone = 3.14 r^2 h/3

Volume of a cone = 3.14 7^2 14/3

Volume of a cone = 3.14 (49) 14/3

Volume of a cone = 3.14 (686)/3

Volume of a cone = 2154/3

Volume of a cone = 718.01

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4 years ago

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3 years ago

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The number of trees planted by the alpine Nursery in April was three more than twice the number of trees planted by the nursery

Readme [11.4K]

Answer:

There were 34 trees planted in March

Step-by-step explanation:

* Lats explain how to solve the problem

- The number of trees planted by the alpine Nursery in April was

three more than twice the number of trees planted by the nursery

in March

- Assume that the number of trees planted in March is x

∵ The number of trees in April was three more than twice the

number of trees on March

∵ The number of trees on March was x

∴ The number of trees in April = 2x + 3

- There were 71 trees planted in April

∵ The number of trees were planted on April was 71

∵ The number of trees in April = 2x + 3

∴ 2x + 3 = 71

- Subtract 3 from both sides

∴ 2x = 68

- Divided both sides by 2

∴ x = 34

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∴ There were 34 trees planted in March

7 0

3 years ago

A student researcher compares the heights of American students and non-American students from the student body of a certain coll

Nonamiya [84]

Answer:

The 90% confidence interval for the difference between means is (4.189, 8.011).

The point estimate is the difference between sample means and has a value of Md=6.1.

Step-by-step explanation:

We have to calculate a 90% confidence interval for the difference between means.

The sample 1 (American students), of size n1=12 has a mean of 69.4 and a standard deviation of 2.79.

The sample 2 (non-American students), of size n2=17 has a mean of 63.3 and a standard deviation of 3.22.

The difference between sample means is Md=6.1.

$M_d=M_1-M_2=69.4-63.3=6.1$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{2.79^2}{12}+\dfrac{3.22^2}{17}}\\\\\\s_{M_d}=\sqrt{0.649+0.61}=\sqrt{1.259}=1.12$

The critical t-value for a 90% confidence interval is t=1.703.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_{M_d}=1.703 \cdot 1.12=1.911$

Then, the lower and upper bounds of the confidence interval are:

$LL=M_d-t \cdot s_{M_d} = 6.1-1.911=4.189\\\\UL=M_d+t \cdot s_{M_d} = 6.1+1.911=8.011$

The 90% confidence interval for the difference between means is (4.189, 8.011).

4 0

3 years ago