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ddd [48]
3 years ago
13

Please help me I’ll give you brainless it’s due in 20 minutes

Mathematics
1 answer:
ankoles [38]3 years ago
7 0

Answer:

*In Explanation

Step-by-step explanation:

<u>1) Start by just substituting the value of x (given in equation 1) into the second equation:</u>

y = 3x - 1

y = 3(2) - 1

y = 6-1 = 5

<u>2) Since both equations have x on one side, make both equations equal to one another:</u>

2y + 4 = 9 - 3y

<u>Solve for y:</u>

5y = 5

y = 1

<u>Plug y = 1 into either one of the given equations and solve for x:</u>

I'll use first equation:

x = 2y + 4

x = 2(1) + 4

x = 6

<u>3) When substituting X into the second equation, remember to use parenthesis:</u>

The student was substituting x from equation 1 into equation 2, but they forgot to multiply ALL of 2y + 3 by 2.

x = 2y + 3

Substitute into 2nd eqn:

y = 2(2y + 3) - 9

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H = 11.81 m


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hope this helped haha
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3 years ago
Plz help me with this assignment! I need help asap!
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A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the
zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

(c) Average power =  1.06 kW

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

d = \frac{1}{2} ({v-0})t

5.5= \frac{1}{2} (1.6v)

The speed of the sprinter then become:

v = 6.875 m/s

Part (b)

Convert the weight of the sprinter to mass:

m = \frac{w}{g}

m = \frac{706}{9.8}

m = 72 kg

KE (Kinetic Energy) can then be calculated as:

KE = \frac{1}{2} mv^{2}

KE = \frac{1}{2} (72)(6.875)^{2}

KE = 1701.56 J = 1.70 kJ

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

P = \frac{KE}{t} \\\

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P = 1063.48 W = 1.06 kW

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