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uranmaximum [27]
2 years ago
13

3.

Mathematics
1 answer:
zaharov [31]2 years ago
7 0

Answer:

Step-by-step explanation:

Lets find the area of the siding

18*14*4, this is 1008

But there are 3 objects

there are two windows that are 1.5 by 2m

Each window has two 1.5 length sides and 2, 2m sides

adding those together is 3 by 4m

then adding these together is 7

The perimeter of the window is 7

then we do that again which would get us to the other window also having a perimeter of 7

adding those together we have a total perimeter of 14

Then we have a door that is 1x2.5

there is 2 2.5 and 2 1 so

1 + 1 is 2

2.5 + 2.5 is 5

thats 7 total

14 + 7 is 21

The total perimeter of those objects is 21

The total area of the siding that we needed before was 1008

From here honestly I dont know what to do because i dont know how area and perimeter work together like this

here u go

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To solve a system of inequalities so you can graph it how do you change these two equations into something like the two that are
Zigmanuir [339]
Explanation

Problem #2

We must find the solution to the following system of inequalities:

\begin{gathered} 3x-2y\leq4, \\ x+3y\leq6. \end{gathered}

(1) We solve for y the first inequality:

-2y\leq4-3x.

Now, we multiply both sides of the inequality by (-1), this changes the signs on both sides and inverts the inequality symbol:

\begin{gathered} 2y\ge-4+3x, \\ y\ge\frac{3}{2}x-2. \end{gathered}

The solution to this inequality is the set of all the points (x, y) over the line:

y=\frac{3}{2}x-2.

This line has:

• slope m = 3/2,

,

• y-intercept b = -2.

(2) We solve for y the second inequality:

\begin{gathered} x+3y\leq6, \\ 3y\leq6-x, \\ y\leq-\frac{1}{3}x+2. \end{gathered}

The solution to this inequality is the set of all the points (x, y) below the line:

y=-\frac{1}{3}x+2.

This line has:

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,

• y-intercept b = 2.

(3) Plotting the lines of points (1) and (2), and painting the region:

• over the line from point (1),

,

• and below the line from point (2),

we get the following graph:

Answer

The points that satisfy both inequalities are given by the intersection of the blue and red regions:

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