Ask question

Ask question

All categories

3 years ago

14

What is the correct answer?

2 answers:

dimaraw [331]3 years ago

8 0

Answer:

the second one

Step-by-step explanation:

Ray Of Light [21]3 years ago

6 0

Answer:

the second answer -&- -&-

You might be interested in

Jael has a monthly budget of x dollars. She spends $1,500 on her mortgage every month. One-fourth of her remaining budget is spe

Alecsey [184]

Answer:

B. y=(x-1500)/4

Step-by-step explanation:

Given that:

Monthly budget = x dollars

Monthly mortgage = $1500

Recreational activities = 1/4 of remaining budget

Amount in dollar spent on recreational activities =

(Monthly budget - monthly mortgage) * 1/4

(x - 1500) * 1/4

Hence,

y = (x - 1500) / 4

5 0

2 years ago

Look at these numbers. 0.3,

timama [110]

0.3.......the 3 is in the tenths place
0.103....the 3 is in the thousandths place
0.13.....the 3 is in the hundredths place

0.3 is ur answer

8 0

3 years ago

Read 2 more answers

Y=6x+20 substitution

Oksana_A [137]

Answer:

-10/3 or -3.33

Step-by-step explanation:

substitute 0 for y

0 = 6x + 20

-20 = 6x + 20 - 20 subtract 20 on both sides

-20 = 6x divide by 6 on each side

-20/6 = 6x/6

x = -20/6 simplify

x = -10/3

8 0

3 years ago

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

3 years ago

If the area of a triangular prism is 300 and the height is 3 what is the area of the base?

evablogger [386]

The volume of any prism is given by
.. V = Bh . . . . B is the area of the base, h is the height

You have
.. 300 = B*3
.. 300/3 = B = 100

The area of the base is 100 square units.

4 0

3 years ago