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n200080 [17]
3 years ago
12

Find the coordinates

Mathematics
1 answer:
Nady [450]3 years ago
3 0

Given:

Midpoint = (2,-14)

One endpoint = (4,-13)

To find:

The another endpoint.

Solution:

Let (a,b) be the another endpoint.

Midpoint formula:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Using midpoint formula, we get

(2,-14)=\left(\dfrac{a+4}{2},\dfrac{b+(-13)}{2}\right)

(2,-14)=\left(\dfrac{a+4}{2},\dfrac{b-13}{2}\right)

On comparing both sides, we get

2=\dfrac{a+4}{2}

4=a+4

4-4=a

0=a

And,

-14=\dfrac{b-13}{2}

-28=b-13

-28+13=b

-15=b

Therefore, the another endpoint is (0,-15).

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Goryan [66]

Answer: (a) P(no A) = 0.935

              (b) P(A and B and C) = 0.0005

              (c) P(D or F) = 0.379

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Step-by-step explanation: <u>Pareto</u> <u>Chart</u> demonstrates a relationship between two quantities, in a way that a relative change in one results in a change in the other.

The Pareto chart below shows the number of people and which category they qualified each public school.

(a) The probability of a person not giving an A is the difference between total probability (1) and probability of giving an A:

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d) Probability of an A or B is also the sum of probabilities of an A and of an B:

P(A or B) = \frac{68}{1052} +\frac{258}{1052}

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7 0
3 years ago
If F(x)=x^3-2x^2, which expression is equivalent to f(I) -2+i,-2-i,2+i,2-i
Romashka-Z-Leto [24]

Hello from MrBillDoesMath!

Answer:

2 - i

Discussion:

Evaluate F(x) = x^3 - 2 x^2 when x = i.

i^2 = -1 for i^3 = i ( i^2) = i (-1) = -i

So F(i) =  (i)^3 - 2 (i)^2                      

          =   -i     - 2(-1)

          = -i      +  2

          =  2      -  i


which is the last answer shown


Thank you,

MrB

6 0
3 years ago
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GREYUIT [131]
 <span>3x + x - 13 + 4 - 6x =12  

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Answer:

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