Are we finding x? Or are we solving the equation with x
Answer:
425.25
Step-by-step explanation:
Since we are given 36th term as 14 and we know common difference is 
, it means that from the first term, we add to each and get 14 on the 36th term. To figure out the first term, thus, we have to subtract 35 times from 14. Let's do it to get first term:
The sum of arithmetic sequence formula is:
![S_{n}=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Where,
is the sum of nth term (we want to figure this out for first 36 terms)
is the first term (we figured this out to be 9.625)
is the term number (36 for our case)
is the common difference (given as )
Substituting all the values, we get:
![S_{36}=\frac{36}{2}[2(9.625)+(36-1)(\frac{1}{8})]\\S_{36}=18[19.25+4.375]\\S_{36}=18[23.625]\\S_{36}=425.25](https://tex.z-dn.net/?f=S_%7B36%7D%3D%5Cfrac%7B36%7D%7B2%7D%5B2%289.625%29%2B%2836-1%29%28%5Cfrac%7B1%7D%7B8%7D%29%5D%5C%5CS_%7B36%7D%3D18%5B19.25%2B4.375%5D%5C%5CS_%7B36%7D%3D18%5B23.625%5D%5C%5CS_%7B36%7D%3D425.25)
First answer choice is right.
U need to use the distributive property ok? The u have to add or subtract the number on both sides bring it down and the you have to divide
Answer:
you average the scores by adding scores from exam 1 and exam 2 then divide it by 2 to average the exam scores
Step-by-step explanation:
