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son4ous [18]
3 years ago
9

Differentiate

rmula1" title=" \sqrt{x} + \frac{1}{5x} - 3" alt=" \sqrt{x} + \frac{1}{5x} - 3" align="absmiddle" class="latex-formula">
with respect to their variable ​
Mathematics
1 answer:
Leviafan [203]3 years ago
3 0

\\ \tt\longmapsto \dfrac{d}{dx}\sqrt{x}+\dfrac{1}{5x}-3

\\ \tt\longmapsto \dfrac{d}{dx}x^{\frac{1}{2}}+5x^{-1}-3

  • Derivative of any constant is 0

\\ \tt\longmapsto \dfrac{d}{dx}x^{\frac{1}{2}}+5x^{-1}

\boxed{\sf \dfrac{d(x^n)}{dx}=nx^{n-1}}

\\ \tt\longmapsto \dfrac{1}{2}x^{\frac{-1}{2}}-5x^{-2}

\\ \tt\longmapsto \dfrac{x}{2}^{\frac{-1}{2}}-\dfrac{1}{5x^2}

\\ \tt\longmapsto -\sqrt{\dfrac{x}{2}}-\dfrac{1}{5x^2}

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Thoes are two separate questions number 10 and 11. Please help​
DerKrebs [107]

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7 0
3 years ago
If you can, please leave an explanation so I can learn how to do it rathe than just copying
castortr0y [4]

Answer:

Point-Slope: y+1=-5/7(x-5)

Slope Intercept: y=-5/7x+ 2 4/7

Standard: -5x+7y=18

Step-by-step explanation:

<u>Slope: -5/7</u>

Point slope is when the equation is in y-y1=m(x-x1) form.

I used the point (5,-1) but it really <u>doesn't matter</u> which one

Substitute it into (x1,y1)

y--1=-5/7(x-5)

y+1=-5/7(x-5) **2 minus signs is equal to 1 plus sign**

Slope-intercept is when the equation is in y=mx+b form.

y=-5/7x+b

To solve for b, plug in one of the points (again, I choose to use (5,-1)

(-1)=-5/7(5)+b

-1=-25/7+b is equal to asking -1=-3 4/7+b

b=2 4/7

Standard form is when it is in Ax+By=C

We'll covert from slope intercept to standard: y=-5/7+ 2 4/7

y=-5/7x+ 2 4/7 is the same as y=(-5/7x+ 18/7)

7y=5x+18 **Multiply both sides by 7, the common denominators**

-5x+7y=18 **Subtract 5x from both sides**

<em>Sorry it took it while to get everything down but I hope this helps~</em>

6 0
3 years ago
In a game of poker a hand of five cards is dealt to each player from a deck of 52 cards. find the probablility of a hand contain
aalyn [17]

Answer:

0.00597

Step-by-step explanation:

Given,

Total number of cards = 52,

In which flush cards = 20,

Also, the number of spade flush cards = 5,

Since,

\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Thus, the probability of a hand containing a spade flush, if each player has 5 cards

=\frac{\text{Ways of selecting a spade flush card}}{\text{Total ways of selecting five cards}}

=\frac{^{20}C_5}{^{52}C_5}

=\frac{\frac{20!}{5!15!}}{\frac{52!}{5!47!}}

=\frac{15504}{2598960}

= 0.00597  

7 0
3 years ago
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