Answer:
4 pounds and 1/4 ounces
Step-by-step explanation:
8 and 1 half pounds = 8.5 Ibs
One half of 8.5 = 8.5/2 = 4. 25 Ibs or 4 & 1/4 or 4Ibs 4 ounces.
Okay, first we need to figure out what one would make. We need to figure out the area of the base x height. The diameter is 8 so we will cut that to 4 so we can do piR2! 3.14x16 would be 50.24. Then we mutiply that by 10 to get 502.4cm3! Okay, now we would divide 2000/502.4 to find out how many times we would have to make the containers to get to 2000. The answer is 3.98, which we will have to round up since its asks for the minimum and you cant make a container 3.98 times. So the answer is 4!
Step-by-step explanation:
Given:
![\vec{\textbf{F}}(x, y, z) = ye^z\hat{\textbf{i}} + xe^z\hat{\textbf{j}} + xye^z\hat{\textbf{k}}](https://tex.z-dn.net/?f=%5Cvec%7B%5Ctextbf%7BF%7D%7D%28x%2C%20y%2C%20z%29%20%3D%20ye%5Ez%5Chat%7B%5Ctextbf%7Bi%7D%7D%20%2B%20xe%5Ez%5Chat%7B%5Ctextbf%7Bj%7D%7D%20%2B%20xye%5Ez%5Chat%7B%5Ctextbf%7Bk%7D%7D)
A vector field is conservative if
![\vec{\nabla}\textbf{×}\vec{\text{F}} = 0](https://tex.z-dn.net/?f=%5Cvec%7B%5Cnabla%7D%5Ctextbf%7B%C3%97%7D%5Cvec%7B%5Ctext%7BF%7D%7D%20%3D%200)
Looking at the components,
![\left(\vec{\nabla}\textbf{×}\vec{\text{F}}\right)_x = \left(\dfrac{\partial F_z}{\partial y} - \dfrac{\partial F_y}{\partial z}\right)_x](https://tex.z-dn.net/?f=%5Cleft%28%5Cvec%7B%5Cnabla%7D%5Ctextbf%7B%C3%97%7D%5Cvec%7B%5Ctext%7BF%7D%7D%5Cright%29_x%20%3D%20%5Cleft%28%5Cdfrac%7B%5Cpartial%20F_z%7D%7B%5Cpartial%20y%7D%20-%20%5Cdfrac%7B%5Cpartial%20F_y%7D%7B%5Cpartial%20z%7D%5Cright%29_x)
![= xe^z - ye^z \neq 0](https://tex.z-dn.net/?f=%3D%20xe%5Ez%20-%20ye%5Ez%20%5Cneq%200)
Since the x- component is not equal to zero, then the field is not conservative so there is no scalar potential
.
We know that AD is the same length as DC, so therefore we can say:
y+6=2y
Move y over to the right side of the equation
6=y
Since DC is equal to 2y, DC would equal 6x2=12
Please find illustration attached
Answer and explanation:
I have illustrated the bisection of the lines using a diagram so it's easier to solve length of AB
Comparing line DE and CB, we know that DE is half of line DC and DC is half of CB, because CB= AC
Therefore DE is a quarter of line CB because length of DE × 4 will be equal to CB
To find length of AB, we go from known to unknown
We know from what we are given that line AB has a midpoint C, CB in line AB = 3x²+3x
CB=AC because CB is half of line AB
Therefore line AB
=3x²+3x+3x²+3x
= 6x²+6x