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3 years ago

Answer asap pls no wrong answers

Mathematics

2 answers:

ddd [48]3 years ago

7 0

Answer:

A. 3,6, $\sqrt45$

Step-by-step explanation:

elena-14-01-66 [18.8K]3 years ago

4 0

The answer is 3,6 46

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Two bicyclists started racing towards each other when they were 98 miles apart. Three hours later they did not yet meet and the

tatyana61 [14]

83 mh i think but im not sure

4 0

3 years ago

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Toby skated from his house to the beach at a constant speed of 888 kilometers per hour, and then skated from the beach to the pa

attashe74 [19]

Answer:

8b+7p=20

p = 2b

Step-by-step explanation:

Given that there is a constant speed of 8 km per hour and the number of hours be b so here 8b signifies the distance

Now on the other hand there is a constant speed of 7 km per hour and the number of hours be p so here 7p signfies the distance

So the total distance would be

= 8b + 7p

And, the total km is 20

Now the whole equation would be

8b + 7p = 20

Also it is mentoined that for getting into the park it is twice for getting into the beach

So, it would be

p = 2b

Therefore the system of equations are as follows

8b+7p=20

p = 2b

5 0

3 years ago

Please help lol!!!!!!!

Elena L [17]

Answer:

That would be 4x - 3y + 5

Step-by-step explanation:

Hope this helps

8 0

3 years ago

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Chase took a taxi from his house to the airport the taxi company charged a pick up fee $1.20 plus $4.75 Per mile . The total far

taurus [48]

I believe that the taxi went 10 miles

3 0

3 years ago

Which students line segments have a midpoint of (-1,4)? Select all that apply A. Student 1 B. Student 2 C. Student 3 D. Student

SashulF [63]

Answer:

C. Student 3

E. Student 5

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

Verify the midpoint of each student

student 1

we have the endpoints

(-9,0) and (11,-8)

substitute in the formula

$M(\frac{-9+11}{2},\frac{0-8}{2})$

$M(1,-4)$

The midpoint is not (-1,4)

student 2

we have the endpoints

(-6,-1) and (4,-7)

substitute in the formula

$M(\frac{-6+4}{2},\frac{-1-7}{2})$

$M(-1,-4)$

The midpoint is not (-1,4)

student 3

we have the endpoints

(-5,2) and (3,6)

substitute in the formula

$M(\frac{-5+3}{2},\frac{2+6}{2})$

$M(-1,4)$

The midpoint is equal to (-1,4)

student 4

we have the endpoints

(-3,10) and (5,-2)

substitute in the formula

$M(\frac{-3+5}{2},\frac{10-2}{2})$

$M(1,4)$

The midpoint is not (-1,4)

student 5

we have the endpoints

(0,-3) and (-2,11)

substitute in the formula

$M(\frac{0-2}{2},\frac{-3+11}{2})$

$M(-1,4)$

The midpoint is equal to (-1,4)

therefore

Student 3 and student 5

3 0

4 years ago