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Andreas93 [3]
3 years ago
5

HELP PLEASE!! Please don't give me sites or links, those won't work since the site is blocked!

Mathematics
1 answer:
larisa86 [58]3 years ago
6 0

Answer:

x <= 1/4 (less than or equal to)

Step-by-step explanation:

In this equation, all you need to do is isolate the variable. To do this, you just move everything that isn't x to the right side. To get rid of the 4, divide both sides by 4. Your result will be x <= 1/4.

Note: Since we're dividing both sides by a positive number, we don't have to change the direction of the inequality. If you were to divide both sides by -1 you would have to reverse the inequality. Example:

x > 1 or 5 > 1

-x < -1 or -5 < -1

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Any advice on algebra 1 leap test, I'm a middle schooler taking it and a bit nervous
Julli [10]
Here is some pro tips, I take algebra 1, and I’m in middle school too.
x * x = x^2
If you see anything like (x + 5)(x - 5), solve using FOIL, (front, outer, inner, last), it’s basically the distributive property for four numbers and x’es.
Distributive property is a must know.
And also, if you are feeling nervous, remember, even if you fail the leap test, it doesn’t make you less of a intelligent, kind, and caring person.
5 0
3 years ago
I need feedback on this problem.
serious [3.7K]

Answer:

B

Step-by-step explanation:

Thats how the answer is none of the others make sense

3 0
3 years ago
A store sells televisions for $360 and DVD burners for $270. The entire stock is worth $52,920 and there are a total of 164 tele
bogdanovich [222]

Answer:  96 Televisions, 68 DVD burners

<u>Step-by-step explanation:</u>

Let T represent the quantity of televisions

Let D represent the quantity of DVD burners

<u>Given:</u>

value of television (T) = 360

value of DVD burners (D) = 270

Total value = 52,920

<u>Equations:</u>

Value: 360T + 270D = 52,920

Quantity:   T + D = 164

We can solve the system of equations using the Elimination Method:

-1(360T + 270D = 52,920) →  -360T - 270D = -52,920

  360(T + D = 164) →                <u>360T + 360D</u> = <u>59,040 </u>

                                                                90D = 6,120

                                                              <u> ÷90   </u>  <u> ÷90    </u>

                                                                     D = 68

Input the value of D into one of the equations to solve for T

T + D = 164

T + 68 = 164

      T   = 96

6 0
3 years ago
The desired percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is 5.5. To test whether the true average
Reil [10]

Answer:

a)  Null hypothesis : H₀ : μ = 5.5

 Alternative Hypothesis : H₁ : μ < 5.5

b) The test statistic

        |t| = |-3.33| = 3.33

c) P - value lies between in these intervals

0.001 < P < 0.005

Step-by-step explanation:

<u><em>Step( i )</em></u>:-

Given data the Population mean 'μ' = 5.5

The small sample size 'n' = 16

The sample mean (x⁻) = 5.25

Given the  percentage of SiO2 in a sample is normally distributed with a sigma of 0.3.

<u><em> Null hypothesis : H₀ : μ = 5.5</em></u>

<u><em>  Alternative Hypothesis : H₁ : μ < 5.5</em></u>

 Level of significance ∝ = 0.01

<u><em>Step(ii)</em></u>:-

 The test statistic

                              t = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }

                             t = \frac{5.25 -5.5}{\frac{0.3}{\sqrt{16} } }

On calculation , we get

                            t = -3.33

                           |t| = |-3.33| = 3.33

<u><em>Step(iii)</em></u>:-

<u><em>P - value</em></u>

<u><em>The degrees of freedom γ = n-1 = 16-1 =15</em></u>

The calculated value t = 3.33 (check t-table) lies between the 0.001 to 0.005

0.001 < P < 0.005

<u>Condition(i)</u>

P - value < ∝ then reject H₀

<u>Condition(ii)</u>

P - value > ∝ then Accept H₀

we observe that  0.001 < P < 0.005

P- value < 0.01

we rejected  H₀

<em>(or)</em>

The tabulated value  = 2.60 at 0.01 level of significance with '15' degrees of freedom

The calculated value t = 3.33 > 2.60 at 0.01 level of significance with '15' degrees of freedom

The null hypothesis is rejected

<u><em>Conclusion</em></u>:-

Accepted Alternative hypothesis H₁

The Claim that the true average is smaller than 5.5

<u><em></em></u>

             

4 0
3 years ago
Solve the following linear inequality: <br><br>3(x + 4) ≥ 5x – 123
Tpy6a [65]
3(x+4)\geq5x-123\\3\cdot x+3\cdot4\geq5x-123\\3x+12\geq5x-123\ \ \ \ /-12\\3x\geq5x-135\ \ \ \ /-5x\\-2x\geq-135\ \ \ /:(-2) < 0\ then\ "\geq"\ change\ "\leq"\\x\leq67.5\\\\x\in(-\infty;\ 67.5 >
6 0
3 years ago
Read 2 more answers
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