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Deffense [45]
3 years ago
13

The sum of two numbers is 100. The different between them is 56. What is the larger number?

Mathematics
1 answer:
m_a_m_a [10]3 years ago
3 0
<h2><u>An</u><u>swer</u><u>:</u><u>-</u></h2>

\pink{\bigstar} The larger number is \large\leadsto\boxed{\tt\purple{78}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>• <u>Given</u><u>:</u><u>-</u></h3>

  • Sum of two numbers is 100.

  • Difference between the numbers is 56.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>• <u>To</u><u> </u><u>Find</u><u>:</u><u>-</u></h3>

  • The larger number = ?

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>• <u>Solut</u><u>ion</u><u>:</u><u>-</u></h3>

Let the two numbers be 'x' and 'y' respectively.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<u>According to the question:-</u>

✯ Sum of two numbers is 100.

➪ \sf x + y = 100 \dashrightarrow\bold\red{[equation \: 1]}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Also,

✯ Difference between the numbers is 56.

➪ \sf x - y = 100 \dashrightarrow\bold\red{[equation \: 2]}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• <u>Adding</u><u> </u><u>eq</u><u>uation</u><u> </u><u>[</u><u>1</u><u>]</u><u> </u><u>a</u><u>nd</u><u> </u><u>equat</u><u>ion</u><u> [</u><u>2</u><u>]</u><u>:</u><u>-</u>

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf (x + y) + (x - y) = 100 + 56

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf x + y + x - y = 156

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf 2x = 156

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf x = \dfrac{156}{2}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

★ \large{\bold\red{x = 78}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• <u>Subst</u><u>ituting</u><u> </u><u>the</u><u> </u><u>va</u><u>lue</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>in</u><u> </u><u>equa</u><u>tion</u><u> </u><u>[</u><u>1</u><u>]</u><u>:</u><u>-</u>

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf x + y = 100

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf 78 + y = 100

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf y = 100 - 78

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

★ \large{\bold\red{y = 22}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Therefore, the numbers are 78 and 22.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

The larger number is 78.

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Situation of non- proportional relationship :

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The radius of a circle with a diameter of x units can be represented by y = \frac{1}{2}x

a proportional relationship is a relationship between two quantities in which the ratio of one quantity to the other quantity is constant. The graph of a proportional relationship is a line through the origin.

When ratios between quantities are not constant, a relationship may be linear but not proportional and the graph does not pass through the origin.

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8 0
2 years ago
HELP ME
kherson [118]

Answer: 18

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7 0
3 years ago
If <img src="https://tex.z-dn.net/?f=%20%28x%2By%29%5E%7B2%7D%20%20" id="TexFormula1" title=" (x+y)^{2} " alt=" (x+y)^{2} " al
olga_2 [115]

(x + y)^2 = 36


x^2 + 2xy + y^2 = 36


x^2+ y^2 = 36 - 2xy = 36- 2(-7)= 36+14=50


Answer: 50




4 0
3 years ago
Ariel wants to write 8 entries for her blog. After 2 hours, she has 5 entries left. After 4 hours, she has 2 entries left. Which
mash [69]

Let x be a time in hours and y be an amount of remaining entries. You have that:

  • At start Ariel wants to write 8 entries for her blog. This means that x=0 and y=8 (0 entries were written). The point with coordinates (0,8) belongs to needed graph.
  • After 2 hours, she has 5 entries left. This gives you that at x=2, y=5 and graph passes through the point (2,5).
  • After 4 hours, she has 2 entries left. This gives you that at x=4, y=2 and graph passes through the point (4,2).

Find the slope of the line that is passing through the points (x_1,y_1) and (x_2,y_2)  by formula

\dfrac{y_2-y_1}{x_2-x_1}.

Thus, the slope is

\dfrac{5-2}{2-4}=-1.5.

Answer: graph of line going through (0, 8) with a slope of -1.5

6 0
3 years ago
Read 2 more answers
find the values of x and y that make these triangles congruent by the hl theorem x=2,y=3 x=-2,y=3x=3,y=2x=4,y=8
AnnyKZ [126]

Answer:

The correct option is x=3 , y=2

Step-by-step explanation:

According to the HL theorem if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

Now we will plug the value y+1 of equation 1 in equation 2.

2x+3 = 3y+3

2(y+1)+3=3y+3

2y+2+3=3y+3

2y+5=3y+3

Now combine the like terms:

5-3=3y-2y

2=y

y=2

Now plug the value y=2 in equation 1.

x=y+1

x=2+1

x=3

Thus the values of(x.y) are{(2,3)}

Therefore the correct option is x=3 , y=2 .....

3 0
3 years ago
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