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Leokris [45]
4 years ago
15

Chelsea invested %5600 at a rate of 3.6% compounded quarterly. Write a compound interest function to model the situation. Then f

ind the balance after 6 years.
Mathematics
1 answer:
grigory [225]4 years ago
5 0
3.6% compounded quarterly=.036/4=0.009 per period
FV=5600(1+.009)^4y where FV=future value, and y is time, in years. So:
FV(6)=5600(1.009)^4(6)=5600(1.009)^24=$6943.46
☺☺☺☺
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Leigh is going diving and needs to descend to a depth of 360 feet below sea level. She wants to do it in 12 equal descents. How
IgorLugansk [536]

Answer:

Leigh would need to descend by 30 feet every 12 intervals

Explanation:

If Leigh wishes to travel 360 feet in 12 equal intervals they would need to divide 360 into 12 equal parts resulting in such that the value of 360 would equal 30 12 times I hope this can help have a wonderful day ^^

8 0
4 years ago
Read 2 more answers
Six times a number equals 3 times the number, increased by 12. Find the number
tino4ka555 [31]

Answer:

x=4

Step-by-step explanation:

"A number" can be rewritten as X:

6x=3x+12

1) subtract 3x on both sides:

3x=12

2) divide both sides by 3:

x=4

4 0
3 years ago
The aquarium display 322 fish . the number of seahorses on display is 85 less than the number of fish
Ugo [173]

There is 237 seahorses.

If there's 322 fish and 85 less seahorses, do 322-85=237.

8 0
4 years ago
At a college campus, random drug tests are carried out to prevent use of prohibited drugs by athletes. Of all the athletes on ca
saw5 [17]

Answer:

a) 0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

b) 0.2693 = 26.93% probability that this drug user never used the prohibited drug.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

A. If an athlete is selected at random, what is the probability that athlete will test positive for prohibited drug use?

100 - 5 = 95% of 8%

100 - 13 = 87% of 17%

11% of 75%

So

p = 0.95*0.08 + 0.87*0.17 + 0.11*0.75 = 0.3064

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

B. If an athlete tests positive after a drug test, what is the probability that this drug user never used the prohibited drug?

Conditional Probability

Event A: Tests Positive

Event B: Never used the drug.

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use

This means that P(A) = 0.3064

Probability of testing positive while never using the drug.

11% of 75%. So

P(A \cap B) = 0.11*0.75 = 0.0825

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0825}{0.3064} = 0.2693

0.2693 = 26.93% probability that this drug user never used the prohibited drug.

8 0
3 years ago
A watch cost $75.99. If the sales tax rate is 6.25%. What is the amount of sales tax
kkurt [141]

Answer:

i DON'T KNOW............

Step-by-step explanation:

6 0
3 years ago
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