the complete question is
Find two numbers whose difference is 46 and whose product is a minimum
Let
x------->larger number
y-------> smaller number
P-------> product of the two numbers
we know that
-----> equation 1
-----> equation 2
substitute equation 1 in equation 2
![P=x*[x-46]\\ P=x^{2} -46x](https://tex.z-dn.net/?f=%20P%3Dx%2A%5Bx-46%5D%5C%5C%20P%3Dx%5E%7B2%7D%20-46x%20)
using a graph tool
see the attached figure
Find the value of x for that the product P is a minimum
the vertex is the point 
that means, for 
the product is a minimum 
find the value of y
therefore
the answer is
the numbers are 
and 
Answer:
I cant see the table
Step-by-step explanation:
X = -1!
1. Factor out 2 from the expression : 2(x-5) / 4 = 3x
2. Reduce the fraction with 2 : x-5 / 2 = 3x
3. Multiply both sides of the equation by 2 : x-5=6x
4. Move the terms : x - 6x = 5
5. Collect like terms : -5x = 5
6. Divid both sides by -5
Hope this helps!
80
8 x 10
2 x 4 x 5 x 2
2 x 2 x 2 x 2 x 5 <===
Answer:
everything but 4 and 31!
Step-by-step explanation:
24: 9+9+1+1+1+3
29: 9+5+5+1+1+3
56: 9×6
