S = ut + (1/2)a(t²) Subtract ut from both sides
(1/2)a(t²) = S - ut Multiply both sides by 2
a(t²) = 2s - 2ut Divide both sides by t²
a= 2s/t² - 2u/t

a= (2S - 2ut)/t²

Answer is C) but there should be parentheses around the term (2S-2ut)

5 0

3 years ago

What is an equation of the line that passes through the point (-4,-6) and is perpendicular to the line 4x+5y=25

elixir [45]

Answer:

$y = \frac{5}{4} x - 1$

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is its gradient and c is its y-intercept.

First rewrite the equation of the given line in the form of y=mx +c.

4x+5y=25

5y= -4x +25

$y = - \frac{4}{5} x + 5$

The gradient of the given line is $- \frac{4}{5}$

The product of the gradient of perpendicular lines is -1.

$( - \frac{4}{5} )(gradient \: of \: line) = - 1 \\ gradient \: of \: line = - 1 \div ( - \frac{4}{5} ) \\ gradient \: of \: line = \frac{5}{4}$

Thus, m= $\frac{5}{4}$

$y = \frac{5}{4} x + c$

Substitute a coordinate to find c.

When x= -4, y= -6,

$- 6 = \frac{5}{4} ( - 4) + c \\ - 6 = - 5 + c \\ c = 5 - 6 \\ c = - 1$

Hence, the equation of the line is

$y = \frac{5}{4} x - 1$

7 0

3 years ago

Find the solution for 30 − 5n ≤ 25.<br> 1 n ≤ -1<br> 2 n ≤ -11<br> 3 n ≥ -11<br> 4 n ≥ 1

Anit [1.1K]

Answer:

n>=1

Step-by-step explanation:

30-5n<=25

5n<=30-25

5n<=5

n<=5/5

n<=1

n>=1

3 0

3 years ago

I need help with this please​

I need help with this please