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Kitty [74]
3 years ago
5

6x+3y=15 ordered pair to this solution

Mathematics
2 answers:
Oduvanchick [21]3 years ago
7 0

Answer:

6x+3y=15 ordered pair to this solution

Step-by-step explanation:

6x+3y=15 ordered pair to this solution

6x+3y=15 ordered pair to this solution

Murrr4er [49]3 years ago
6 0

Answer:

5

Step-by-step explanation:look it up

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What is the value of 7(10 – 16) + 8 ÷ 2?
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−38

First do 10-16 which is -6

(7)(−6)+8/2

=−42+8/2

8/2 equals 4 so add -42 to 4

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3 years ago
Sin∅=√3-1/2 find approximate value of sec∅(sec∅+tan∅)/1+tan²∅​
Neko [114]

Answer:

The approximate value of f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta} is 1.366.

Step-by-step explanation:

Let f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta}, we proceed to simplify the formula until a form based exclusively in sines and cosines is found. From Trigonometry, we shall use the following identities:

\sec \theta = \frac{1}{\cos \theta} (1)

\tan\theta = \frac{\sin\theta}{\cos \theta} (2)

\cos^{2}+\sin^{2} = 1 (3)

Then, we simplify the given formula:

f(\theta) = \frac{\left(\frac{1}{\cos \theta} \right)\cdot \left(\frac{1}{\cos \theta}+\frac{\sin \theta}{\cos \theta}\right) }{1+\frac{\sin^{2}\theta}{\cos^{2}\theta} }

f(\theta) = \frac{\left(\frac{1}{\cos^{2} \theta} \right)\cdot (1+\sin \theta)}{\frac{\sin^{2}\theta + \cos^2{\theta}}{\cos^{2}\theta} }

f(\theta) = \frac{\left(\frac{1}{\cos^{2}\theta}\right)\cdot (1+\sin \theta)}{\frac{1}{\cos^{2}\theta} }

f(\theta) = 1+\sin \theta

If we know that \sin \theta =\frac{\sqrt{3}-1}{2}, then the approximate value of the given function is:

f(\theta) = 1 +\frac{\sqrt{3}-1}{2}

f(\theta) = \frac{\sqrt{3}+1}{2}

f(\theta) \approx 1.366

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3 years ago
Help .. A. 600, 0 B. 50, 350 C. 0, 500
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Answer:

C.0, 500

Step-by-step explanation:

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