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Anna11 [10]
2 years ago
7

HELP!!!! If u answer in less then 4 minutes i will give lots of points! PLEASE

Mathematics
1 answer:
galben [10]2 years ago
8 0

Answer:

the answer would be (4) or y=x+5

Step-by-step explanation:

-4+5 = 1 y=1 check

0+5=5 y=5 check

and so on.

You might be interested in
What is the distance between the points (-3, 1) and (1, 3)?
Murrr4er [49]

Answer:

4.47

Step-by-step explanation:

a^2+b^2=c^2

2^2+4^2=c^2

4+16=c^2

20=C^2

\sqrt{20}= \sqrt{c^2}

4.47=c

3 0
2 years ago
Please help!! ASAP
Kryger [21]

Answer:

The answer is 117.3 in^{3}.

Step-by-step explanation:

To solve for the volume of the cone, use the cone volume formula, which is   V = \frac{1}{3} \pi  r^{2} h.

Next, plug in the information given from the problem, and the formula will look like V = \frac{1}{3} (\pi) (4 in^{2}) (7 in).

Then, solve the equation, and the answer will be 117.3 in^{3}.

6 0
2 years ago
12 ÷ 4 + (3 − 2) × 7
Andre45 [30]

Answer: step-by-step

Step-by-step explanation:

answer: 10

to solve you have to follow PEMDAS

3 0
2 years ago
Convert into a decimal degree measure. 165° 37' 44"
andrew11 [14]

Answer:

165.628° (The 8 has a line over it signalizing that it repeats forever, but I didn't know how to put it in.)

Step-by-step explanation:

Since 165 is whole number, it is a full degree. Since each minute is equal to 1/60 degrees, you need to multiply 37 by 1/60. Since each second is equal to 1/3600 degrees, multiply it 1/3600 by 44. Add them all together.

165 + 37 x 1/60 + 44 x 1/3600

simplify: 74533/450

Convert the fraction into a decimal by dividing the numerator by the denominator and you get 165.628° (with a repeating 8).

4 0
3 years ago
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
3 years ago
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