Help me please I don’t understand how to find the parallel or perpendicular

Mathematics

1 answer:

andreev551 [17]3 years ago

5 0

Slope-Intercept Form: y = mx + b, with m = slope and b = y-intercept

So remember that parallel lines have the same slope, while perpendicular lines have slopes that are negative reciprocals to each other. But first, we have to find out the slope of the original equation. The easiest method to find the slope is to convert this standard form equation to slope-intercept form.

Firstly, subtract 6x on both sides of the equation: $-4y=-6x-3$

Next, divide both sides by -4 and your slope-intercept form is $y=\frac{3}{2}x+\frac{3}{4}$

Now, looking at our slope-intercept form we see that the slope of the original equation is 3/2. Using what we know about parallel and perpendicular lines, the slope of a parallel line is 3/2 and the slope of a perpendicular line is -2/3

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Find the equation of the line that is perpendicular to the line

ddd [48]

Answer:

$y=-x+16$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)
Perpendicular lines always have slopes that are negative reciprocals (ex. 3 and -1/3, 5/6 and -6/5, etc.)

1) Determine the slope (m)

y=x-9

Rewrite the equation

y=1x-9

Now, we can identify clearly that the slope of the line is 1. The negative reciprocal of 1 is -1, so therefore, the slope of a perpendicular line would be -1. Plug this into $y=mx+b$ :

$y=-1x+b\\y=-x+b$