Answer:
The speed rate of the plane in still air is 1006.67 km/h
The speed rate of the wind is 246.67 km/h
Step-by-step explanation:
To answer the question, we let the speed of the plane in still air = x km/h
Let the speed of the wind = y km/h
Therefore,
4560/(x - y) = 6 hours and
3720/(x + y) = 3 hours
4560 = 6·x - 6·y.........(1)
3720 = 3·x + 3·y ........(2)
Multiplying equation (2) by 2 and add to (1) gives
12080 = 12·x
x = 12080/12 =
km/h
Substituting the value of x in (1) gives
4560 = 6040 - 6·y
6·y = 1480
y = 1480/6 = 
The speed rate of the plane in still air = 1006.67 km/h
The speed rate of the wind = 246.67 km/h.
Answer:
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Step-by-step explanation:
sorry
Answer:
It should be the first quadrant
Hope that helps!
Think of PEMDAS. PEMDAS is Parenthesis, Exponets, Multiplication, Division, Add, and Subtract. We don't have any Parenthesis, we don't have any Exponets, we do have multiplication: 34•8. I think it's A. 34•8
14/16 divided by 2 is 7/8 or D.