The third tree diagram is correct.
The probabilities for the first draw are 3/7 for green and 4/7 for red.
If you draw a green pear first, then your probabilities for the second pear would be 2/6 for green and 4/6 for red (since it is done without replacement, the number of pears to choose from changes).
If you draw a red pear first, then your probabilities for the second pear would be 3/6 for green and 3/6 for red.
1:9 is the ratio
You can check this by converting the feet to inches and dividing the greatest number by the smaller number.
Answer:
Step-by-step explanation:
An = 54 + 3(n-1)
n = 1 ; A1 = 54 + 3*(1-1) = 54 + 3*0 = 54 +0 = 54
n =2 ; A2 = 54 + 3*(2-1) = 54 + 3*1 = 54 + 3 = 57
n =3 ; A3 = 54 + 3*(3-1) = 54 + 3*2 = 54 + 6 = 60
n =4 ; A4 = 54 + 3*(4-1) = 54 + 3*3 = 54 + 9 = 63
ABC ~ A’B’C’
So, AB=A’B’ , BC=B’C’ , AC = A’C’
Given, AB=15 and A’C’=4
So, AC = 4 , A’B’ = 15
349,009,186,304. Your welcome.
