- Triangle Inequality Theorem: States that the sum of any two sides of a triangle is greater than the length of the third side;
So for this, we are applying the triangle inequality theorem. If any of the inequalities are not true, then this cannot be a triangle. (Let A = 7.7, B = 4.0, and C = 1.7)
<u>Since the second inequality is false, these lengths cannot form a triangle.</u>
Answer:
A cross-section parallel to the base is a rectangle measuring 15 inches by 8 inches.
A cross-section perpendicular to the base through the midpoints of the 8-inch sides is a rectangle measuring 6 inches by 15 inches.
A cross-section not parallel to the base that passes through opposite 6-inch edges is a rectangle measuring 6 inches by greater than 15 inches.
Step-by-step explanation:
the cross sections that are parallel and perpendicular will have the same measurements as the non-intersected sides. the last one will be a diagonal so the intersected edge is 6 and it creates a right triangle so it must be larger than 15 inches.
25/5 5
10/5 2
5/2 is 25/10 but in simplest form
Hello,
To solve we need to factor y^2-2y-35:
(y-7)(y+5)=0
Now solve for :
(When will (y-7)(y+5)equal zero?)
When y-7=0 or y+5=0
Solve for the 2 equations above and;
y= 7,-5
Hope this helps, have a great day!
Answer:
x-y-3=0
Step-by-step explanation:
Choose two common points on the line of intersection of the planes x − z = 3 and y + 2z = 3:
- 1st point: if x=0, then z=-3 and y=3-2z=3+6=9, so the 1st point is (0,-3,9);
- 2nd point: if x=3, then z=0 and y=3-2z=3-0=3, so the 2nd point is (3,0,3).
The perpendicular plane to the plane x+y-4z=6 is parallel to the vector with coordinates (1,1,-4) (normal vector of the given plane).
Hence, the equation of needed plane is
Thus,
