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barxatty [35]
2 years ago
6

Help me plz, 13 points! these questions are separate. help me work out both questions please ​

Mathematics
1 answer:
Taya2010 [7]2 years ago
8 0
2x+20 makes more sense to the math question
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30.00
GalinKa [24]

Answer:

  (13,-23)

Step-by-step explanation:

Comparing the image coordinates to the transformation rule, you see that ...

  (x -4, y +15) = (9, -8)

Adding (4, -15) to these coordinates, we get ...

  (x -4, y +15) +(4, -15) = (9, -8) +(4, -15)

  (x-4+4, y+15-15) = (9+4, -8-15)

  (x, y) = (13, -23) . . . . coordinates of D

4 0
3 years ago
The graph of f(x) = 2x + 3 shifts 10 units to the right when it is replaced with the graph of f(x) = 2x − k. What is the value o
Nezavi [6.7K]

Answer:

k=17

Step-by-step explanation:

Given F(x)=2x+3  shifts 10 units when it is replaced with the graph f(x)=2x-k.

The method to solve this kind of questions is find where the graph meets the x axis then add ten units to it .The obtained x coordinate is the point where the second graph meets the x axis.

Now first find where the F(x)=2x+3 meets the x axis by substituting F(x)=0.

2x+3=0

x=-\frac{3}{2}

Now add 10 to this x coordinate , we get x1=10-3/2=17/2

this is x coordinate where the second line meets the x-axis.

The second line is F(x)=2x-k.

now f(x)=0 and x=17/2

On substitution we get 0=2*17/2-k

k=17

3 0
3 years ago
Find the volume of a pyramid with a square base, where the side length of the base is 14.1 feet and the height of the pyramid is
Korolek [52]

Answer:

= 868.1ft^3

Step-by-step explanation:

Volume of the square based pyramid = BH/3

B is the base area

H is the height of the pyramid

Base area = Length * Length

Base area = 14.1*14.1

BAse area = 198.81ft^2

Height = 13.1feet

Substitute

Volume = 198.81*13.1/3

Volume of the pyramid = 868.1ft^3

Hence the volume of a pyramid with the square base is 868.1ft^3

7 0
2 years ago
Read 2 more answers
What is the remainder when (3x3 â€"" 2x2 4x â€"" 3) is divided by (x2 3x 3)?.
melamori03 [73]

The remainder of the equation is \rm 28x+30.

Given that,

When the equation \rm 3x^3-2x^2+4x-3 is divided by \rm x^2+3x+3.

We have to find,

The remainder of the equation?

According to the question,

The equation \rm 3x^3-2x^2+4x-3 is divided by \rm x^2+3x+3.

On the division of the polynomial, the remainder is,

\dfrac{\rm 3x^3-2x^2+4x-3}{\rm x^2+3x+3}

Factorize the equation to convert this into the simplest form,

\rm 3x^3-2x^2+4x-3\\\\3x^3-11x^2+9x^2+9x+28x-33x-33+30\\\\Taking \ the \ common \ terms \ and \ simplify\  the\  equation\\\\3x^3+9x^2+9x+11x^2+33x-33+28x+30\\\\3x(x^2+3x+3) - 11(x^2+3x+3) + 28x+30\\\\(3x+11) (x^2+3x+3) +28x +30

Now, the equation can be written as,

\rm = \dfrac{(3x+11) (x^2+3x+3) +28x +30}{ x^2+3x+3}\\\\=  \dfrac{(3x+11) (x^2+3x+3) }{ x^2+3x+3} + \dfrac{28x +30}{ x^2+3x+3}\\\\= (3x+11)   + \dfrac{28x +30}{ x^2+3x+3}\\\\

The relation between the divisor, remainder, and quotient is,

\rm = Quotient + \dfrac{Remainder}{Divisor}

On comparing with the equation,

The remainder becomes 28x +30.

Hence, The required remainder of the equation is \rm 28x+30.

For more details refer to the link given below.

brainly.com/question/25880057

7 0
3 years ago
7m – 3m – 6 < 6 Solve each inequality and graph the solution.
irinina [24]

Answer:

3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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