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3 years ago

A class of 40 students elected a class president. There were 12 votes for Candidate A, and 18 votes for Candidate B.

Mathematics

1 answer:

Helen [10]3 years ago

4 0

Hey there, Bulgogi!

The correct answer will be the first one since [I'm assuming] you know that to calculate the percentage of something, it's the amount of that something divided by the total amount but since only 30 students voted [12+18] multiplied by 100.

So, we are calculating the percentage on votes and 12 students voted for Candidate A so our Numerator will be 12 and our Denominator will be the total amount of student who voted, so 30 [or 12+18]

Once put into a fraction, we will get $\frac{12}{12+18}$ which would be equals to 2/5 or 0.4. Now we multiply by 100 and we get a total of 40% for Candidate A.

Thank you for using Brainly.
See you soon!

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Daisy measured the heights of 20 plants.

sergiy2304 [10]

Answer:

30.5 cm

Step-by-step explanation:

Refer to attached

Height of plants (h) >> Frequency >> Midpoint >> Frequency x midpoint
0 <h < 10 >> 1 >> 5 >> 5
10 <h < 20 >> 4 >> 15 >> 60
20 <h < 30 >> 7 >> 25 >> 175
30 <h < 40 >> 2 >> 35 >> 70
40 <h < 50 >> 3 >> 45 >> 135
50 <h < 60 >> 3 >> 55 >> 165

Sum of frequencies = 20

Sum of frequency x midpoint product = 610

Mean height

610/20 = 30.5 cm

5 0

3 years ago

The anand group is a shipping company that has just heard the bad news that in shipment of six televisions, two are defective. p

Marina86 [1]

2/3 or 4/6 chance of the tv to work 1/3 or 2/6 chance it won't work.

3 0

3 years ago

Find the domain of the function y = 3 tan(23x)

solmaris [256]

Answer:

$\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

In other words, the $x$ in $f(x) = 3\, \tan(23\, x)$ could be any real number as long as $x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)$ for all integer $k$ (including negative integers.)

Step-by-step explanation:

The tangent function $y = \tan(x)$ has a real value for real inputs $x$ as long as the input $x \ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

Hence, the domain of the original tangent function is $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

On the other hand, in the function $f(x) = 3\, \tan(23\, x)$ , the input to the tangent function is replaced with $(23\, x)$ .

The transformed tangent function $\tan(23\, x)$ would have a real value as long as its input $(23\, x)$ ensures that $23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

In other words, $\tan(23\, x)$ would have a real value as long as $x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right)$ .

Accordingly, the domain of $f(x) = 3\, \tan(23\, x)$ would be $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

4 0

2 years ago

In parallelogram ABCD , BE=7x−2 and ED=x2−10 .

Stells [14]

I'm assuming that the diagonals intersect at E. Since diagonals of a parallelogram bisect each other, BE=ED.

7x-2=x²-10
x²-7x-8=0
(x-8)(x+1)=0
x = -1, 8

As distance must be positive, we reject the negative case, so x=8.

Thus, BE=ED=54.

5 0

1 year ago

Find the original price of a pair of shoes if the sale price is $40 after a 60% discount

Arturiano [62]

Answer:

Thus, the original price of the pair of shoes was $100.

Step-by-step explanation:

Percentages

After a 60% discount, the sale price is now valued at 100-60=40% of its original price.

If the sale price is $40, then the original price is calculated as

$40 / 40 * 100 = $100

Thus, the original price of the pair of shoes was $100.

Verify applying 60% discount:

$100 - 60*$100/100 = $40

3 0

2 years ago