From the given figure ,
RECA is a quadrilateral
RC divides it into two parts
From the triangles , ∆REC and ∆RAC
RE = RA (Given)
angle CRE = angle CRA (Given)
RC = RC (Common side)
Therefore, ∆REC is Congruent to ∆RAC
∆REC =~ ∆RAC by SAS Property
⇛CE = CA (Congruent parts in a congruent triangles)
Hence , Proved
<em>Additional</em><em> comment</em><em>:</em><em>-</em>
SAS property:-
"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)
<u>also</u><u> </u><u>read</u><u> </u><u>similar</u><u> questions</u><u>:</u> Complete this proof. Given: EC AC, DB AC, ∠A = ∠F Prove: ΔMDF ∼ ΔNCA..
brainly.com/question/16250124?referrer
Consider the proof. Given: Segment AB is parallel to line DE. Prove: AD/DC = BE/EC What is the missing statement in Step 5? A.) AC = BC B.) AC/DC = BC/EC C.) AD...
brainly.com/question/11763540?referrer
Answer:
No idea
Step-by-step explanation:
All of the numbers are the mode, so it is
1982, 1988, 1989, 1994, 1995, 2005
Answer: 4 hours 31 min
Step-by-step explanation: first you need to simplify or solve 4/2 which is 2 because 4 divided by 2 is 2 and on Tuesday he spent 2 hours and 31 min no simply add 2 hours plus 2 hours and 31 min which gives you 4 hours and 31 min
3 of 4 is not the correct way of writing a ratio.