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3 years ago

A class of 40 students elected a class president. There were 12 votes for Candidate A, and 18 votes for Candidate B.

Mathematics

1 answer:

Helen [10]3 years ago

4 0

Hey there, Bulgogi!

The correct answer will be the first one since [I'm assuming] you know that to calculate the percentage of something, it's the amount of that something divided by the total amount but since only 30 students voted [12+18] multiplied by 100.

So, we are calculating the percentage on votes and 12 students voted for Candidate A so our Numerator will be 12 and our Denominator will be the total amount of student who voted, so 30 [or 12+18]

Once put into a fraction, we will get $\frac{12}{12+18}$ which would be equals to 2/5 or 0.4. Now we multiply by 100 and we get a total of 40% for Candidate A.

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The answer is A.

Because it goes 2 down

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3 years ago

Please help! either one would be appreciated.

bearhunter [10]

#2 part b. the equation is 100+3x+2x=180 and part c. is 3x=48 and 2x=32

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Eric purchased three music CDs and a sweatshirt from a band's online store and received a 20% discount. He paid $100 for his pur

emmasim [6.3K]

(3c+s)(100-20)/100=100 multiply both sides by 100

(3c+s)80=10000 divide both sides by 80

3c+s=125 subtract 3c from both sides...

s=125-3c....now let's look at the second situation...

(4c+2s)(100-40)/100=120 multiply both sides by 100

60(4c+2s)=12000 divide both sides by 60

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2c+s=100 subtract 2c from both sides

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s=50

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3 years ago

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Angela decides to recycle a large oatmeal container by using it to hold a friends birthday gift. Then she wraps the container in

Deffense [45]

Answer:

D. 135.37 in²

Step-by-step explanation:

We have that the gift paper consists of two circles and a square.

Thus, we will need to find the area of the circles and the square.

Now, as the diameter of the circle = 4 inches

So, the radius of the circle = $\frac{4}{2}$ = 2 inches

Since, the area of a circle = $\pi r^{2}$

This implies that area of the two circles = $2\times \pi r^{2}$

i.e. Area of the circles = $2\times \pi 2^{2}$

i.e. Area of the circles = $8\pi$

i.e. Area of the two circles = 25.133 in²

Further, one side of the square = 10.5 inches

Thus, the area of the square = $side^{2}$

i.e. Area of the square = $10.5^{2}$

i.e. Area of the square = 110.25 in²

So, the overall area of the gift paper = 25.133 + 110.25 = 135.37 in².

Hence, the amount of paper used by Angela is 135.37 in².

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3 years ago

56 points for whoever answers correctly !

vladimir2022 [97]

We need to use what we know about rectangles to get:

Total length = 2*W + 8ft
Total width = W + 8ft

2) area = 2*W^2 + 24ft*W + 64ft^2

<h3>Working with rectangles:</h3>

We know that rectangles are defined by two measures, width W and length L.

Here we do know that the length of the pool is twice the width, and the width is W, then the length of the pool is:

L = 2*W

And we also have a sidewalk of 4ft all around the pool, now we want to get:

1) The total length and the total width.

This will be equal to the length/width of the pool <u>plus twice the width of the sidewalk</u> (we add it twice because is in both ends) then we have:

Total length = L + 2*4ft = 2*W + 8ft
Total width = W + 2*4ft = W + 8ft

2) Now we want to get an expression for the total area of the pool.

Remember that for a rectangle the area is just the product between the width and the length, so to get the area of the pool with the sidewalk we just take:

area = (total length)*(total width)

area = (2*W + 8ft)*(W + 8ft) = 2*W^2 + 3*W*8ft + 64ft^2

area = 2*W^2 + 24ft*W + 64ft^2

This is the equation that gives the total area as a function of W, the width of the pool.

If you want to learn more about rectangles, you can read:

brainly.com/question/17297081

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3 years ago