First you put (x+5) into the initial function wherever you see x so it becomes
(x+5)^2+3(x+5)-10=x^2+kx+30
(x^2+5x+25)+(3x+15)-10 simplified left side
x^2+8x+30 fully simplified left side
thus k=8
x^2+8x+30=0 to find 0s
-4 + 3.7416573867739i
<span>-4 - 3.7416573867739i
</span>these are the roots you find after using the quadratic formula
the second one is the smallest
Answer:
Domain = {All real values of x EXCEPT x = -5 and x = 7}
Step-by-step explanation:
This is a rational function given as y=\frac{6+9x}{6-|x-1|}y=
6−∣x−1∣
6+9x
The domain is the set of all real value of x for which the function is defined.
For rational functions, we need to find which value of x makes the denominator equal to 0. We need to exclude those values from the domain.
Now
6 - |x-1| = 0
|x-1| = 6
x- 1 = 6
or
-(x-1) = 6
x = 6+1 = 7
and
-x+1=6
x = 1-6 = -5
So, the x values of -5 and 7 makes this function undefined. So the domain is the set of all real numbers except x = -5 and x = 7
Answer:
7512 hours
Step-by-step explanation:
There are 8760 hours in a year.
There are 52 hours on Thursdays and Saturdays in a year.
The number of hours for Thurdays and Saturdays in a year is 1248.
8760-1248= 7512
Answer:
The graph is symmetric about the origin.
The graph does not pass through the origin.
Step-by-step explanation:
We're given:
- the function y=axn
- a = 1
- n is odd
Because a = 1, then the given function can be rewritten as y = n.
The function y = n will produce a horizontal line. Any function in the form of y = a single number, such as 4 or 9.3 will produce a horizontal line.
- The graph is symmetric about the origin.
This is true, given the graph is a horizontal line.
- The graph does not pass through the origin.
This is also true. We're given that n is an odd number. The graph will only pass through the origin if n = 0, and 0 is even.
- The graph has more than one x-intercept.
This would only be true when n = 0, and this isn't possible. So, no.
