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2 years ago

HI THERE WASSUP SO I WAS THINKING FOR YO TO MIJM OK YADAAAAA LET ME JUST GIVE MYSELF DA POINTS

Mathematics

2 answers:

Viefleur [7K]2 years ago

6 0

Answer: CONFUSED LIKE REALLY CONFUSED BUT THANKS

Step-by-step explanation:

dusya [7]2 years ago

4 0

Answer:

heck ya

Step-by-step explanation:

cheese

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Kaylynn read 380 pages of her book last week. She read the same number of pages each day for 5 days.How many pages did Kaylynn r

dmitriy555 [2]

Answer:

She read 76 pages each day

Step-by-step explanation:

380/5=76

8 0

3 years ago

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An evaluation of the habitats of endangered salmon species was performed in Conservation Ecology (December 2003). The researcher

adell [148]

Answer: The habitat quality score will be normally distributed if at least 50% of the total sites are captured

Step-by-step explanation:

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2 years ago

Please help! Forgot to do homework and I really need help! WORTH 30 POINTS!

stepan [7]

Answer:

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7 0

2 years ago

Divide 100 in a ratio of 5:3

bixtya [17]

Answer:

62.5 : 37.5

Step-by-step explanation:

When we divide 100 into 5:3 ratio the parts we make need to add up to 100

5parts +3 parts = 8 parts

100/8 parts = 12.5 are in each part

12.5*5 : 12.5*3

62.5 : 37.5

check our answer 62.5+37.5 = 100 ✅

7 0

2 years ago

Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. The

Tems11 [23]

Answer:

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

They randomly survey 387 drivers and find that 298 claim to always buckle up.

This means that $n = 387, \pi = \frac{298}{387} = 0.77$

84% confidence level

So $\alpha = 0.16$ , z is the value of Z that has a p-value of $1 - \frac{0.16}{2} = 0.92$ , so $Z = 1.405$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.74$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.8$

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

6 0

2 years ago