Answer:
1
Step-by-step explanation:
x-1+ 1 /5*( x-1)=0
(x-1)*6/5=0
x=1
2x-7y=18 _(1)
-2x+4y=5
11y=23 , Y=23/11 sub in 1
2x-7×23/11=18
2x = 18×11 + 7×23
x = ( 198 + 161 )/2 = 359/2
When a perpendicular is dropped from the right-angle (C) to the opposite side AB, the metric relations apply:
BD*BA=a^2 ..........................(1)
AD*AB=b^2...........................(2)
BD*DA=DC^2........................(3)
Given AD=6, AB=24, using metric relation (2) above, we have
b^2=6*24=144
=>
b=sqrt(144)=12
By the way, we conclude that this is a 30-60-90 triangle because b/AB=(1/2)=sin(B) => B=30 degrees.
Answer: b=12
Answer:
Yes if Angle 7 and angle 6 are linear pairs in angles created by a straight line that cuts through parallel lines.
Step-by-step explanation:
Remember that two parallel lines that are cut by a transveral will create 8 angles, which will be similar to each other. Making four pairs of congruent angles means that they will be exactly the same angle located in different parts of the system. So if angles 6 and 7 are congruent, and the lines are cut by a transversal, then the lines are parallel.
Answer:
rectagle
Step-by-step explanation:
