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fomenos
3 years ago
10

aylor and Natsumi are making block towers out of large and small blocks. They are stacking the blocks on top of each other in a

single column. Taylor uses 4 large blocks and 2 small blocks to make a tower 63.8 inches tall. Natsumi uses 9 large blocks and 4 small blocks to make a tower 139.8 inches tall. How tall is each large block and each small block
Mathematics
1 answer:
frozen [14]3 years ago
7 0

Answer:

The height of a large block is of 12.1 inches and of a small block is of 7.7 inches.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x i the height of a large block.

y is the height of a small block.

Taylor uses 4 large blocks and 2 small blocks to make a tower 63.8 inches tall.

This means that:

4x + 2y = 63.8

Simplifying by 2:

2x + y = 31.9

So

y = 31.9 - 2x

Natsumi uses 9 large blocks and 4 small blocks to make a tower 139.8 inches tall.

This means that:

9x + 4y = 139.8

Since y = 31.9 - 2x

9x + 4(31.9 - 2x) = 139.8

9x + 127.6 - 8x = 139.8

x = 12.1

y = 31.9 - 2x = 31.9 - 2(12.1) = 7.7

The height of a large block is of 12.1 inches and of a small block is of 7.7 inches.

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No

Step-by-step explanation:

No, 5cm, 5cm, and 15cm cannot create a triangle because the side lengths do not follow the formula a + b > c. Since 5 + 5 = 10, and 10 is not greater than 15, these side lengths won't be able to form a triangle.

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2 years ago
From a point on a cliff 75 feet above water level, an observer can see a shipThe angle of depression to the ship is d^ How far i
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Answer:

52feet

Step-by-step explanation:

The set up will be a right angle

Let the angle of depression be 30°

The height above the sea level will be the opposite

The distance of the ship from the base is x (adjacent)

Using TOA

Tan theta = opposite/adjacent

Tan 30 = 30/x

x = 30/tan 30

x = 30/0.5774

x = 51.96

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2 years ago
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A

Step-by-step explanation:

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3 years ago
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3 years ago
Triangle BAC was rotated 90° clockwise and dilated at a scale factor of 2 from the origin to create triangle XYZ. Based on these
ANEK [815]

Answer:

The correct option is;

∠A ≅ ∠X

Step-by-step explanation:

The given coordinates of the points of triangle ACB are;

A(-4, 4), C(-1, 3), B(-4, 0)

The given coordinates of the points of triangle XYZ are;

X(0, 8), Y(8, 8), Z(6, 2), therefore, we have

The length. l. of segment is given by the following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)

For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4

For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2

For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8

For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2

For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10

Therefore;

XY ~ AB, XZ ~ BC, ZY ~ AC

Which gives;

∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z

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3 years ago
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