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3 years ago

22. Find the perimeter of the square: 28

Mathematics

1 answer:

sergejj [24]3 years ago

7 0

Answer:

56√2 ≈ 79.20

Step-by-step explanation:

The hypotenuse of an isosceles right triangle is √2 times the side length, so the side length here is ...

s·√2 = 28

s = 28/√2

The perimeter is 4 times the side length, so is ...

P = 4s = 4·28/√2

= 4·28·(√2)/2 . . . . . multiply by (√2)/(√2) to rationalize the denominator

= 56√2 ≈ 79.195959

The perimeter of the square is 56√2, about 79.20 units.

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N 30 divided by (negative 6)?

Shtirlitz [24]

30/-6 equals 5. You’re welcome

8 0

4 years ago

Stan has made a $125.30 monthly deposit into an account that pays 1.5% interest, compounded monthly, for 35 years. he would now

Andrew [12]

The annuity of the monthly deposit into an account that pays 1.5% interest, compounded monthly, for 35 years is $333.71

<h3>What is annuity?</h3>

An annuity is a series of payments made at equal period of time.

future value = annuity x [(1 + i)ⁿ - 1] / i

annuity = $125.30

i = 1.5% / 12 = 0.00125

n = 35 years x 12 months = 420

future value = $125.30 x [(1 + 0.00125)⁴²⁰ - 1] / 0.00125

future value = $69,156.049 ≈ $69,156.05

annuity = [i x (present value)] / [1 - (1 + i)⁻ⁿ]

i = 1.5% / 12 = 0.00125

n = 20 years x 12 months = 240

present value = $69,156.05

annuity = (0.00125 x $69,156.05) / [1 - (1 + 0.00125)⁻²⁴⁰]

annuity = $86.45 / 0.25904

= $333.71

Learn more about annuity;

brainly.com/question/23554766

4 0

2 years ago

95 points <br><br> Simplify (4^9/4^3)^5 Show your work for full credit

dexar [7]

Answer:

$4^{30}$

Step-by-step explanation:

$(4^9/4^3)^5=$
$(4^{9-3})^5=$
$(4^6)^5=$
$4^{6*5}=$
$4^{30}$

3 0

2 years ago

Read 2 more answers

Prove that 3:8 is equivalent to 12:32

Julli [10]

3 times 4 is equal to 12
8 times 4 is equal to 32
therefore 3:8 is equal to 12:32
hope this helps

3 0

3 years ago

Use the graph of f below. Assume the entire function is graphed below.<br> Find the domain

enot [183]

ANSWER

The domain of the function is

$- 3 \leqslant x \leqslant 6$

[-3,6]

EXPLANATION

The domain of a function refers to the values of x for which the function is defined.

From the graph, we can see that the function begins at (-3,6) and ends at (6,-4).

Therefore the function is defined for x=-3 to x=6.

Hence the domain of the function is

$- 3 \leqslant x \leqslant 6$

[-3,6]

5 0

3 years ago