Question

22. Find the perimeter of the square: 28

Answer 1

Answer:

  56√2 ≈ 79.20

Step-by-step explanation:

The hypotenuse of an isosceles right triangle is √2 times the side length, so the side length here is ...

  s·√2 = 28

  s = 28/√2

The perimeter is 4 times the side length, so is ...

  P = 4s = 4·28/√2

  = 4·28·(√2)/2 . . . . . multiply by (√2)/(√2) to rationalize the denominator

  = 56√2 ≈ 79.195959

The perimeter of the square is 56√2, about 79.20 units.