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Advocard [28]
3 years ago
5

Find the volume of the sphere.

Mathematics
1 answer:
Veronika [31]3 years ago
7 0

Answer:

your answer will be 113.04 unit^3

Step-by-step explanation:

hope this helps have a nice day ^_^

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Find the sum of the polynomials below: (7x8 + 3x - 3) + (4x8 + 2x + 5)
Ipatiy [6.2K]
7x^8+3x-3
+4x^8+2x+5
=11x^8+5x+2
6 0
4 years ago
The midpoint of AB is M(-2, 1). If the coordinates of A are (-3,-5),
mrs_skeptik [129]

Answer:

B= (-1, 7)

Step-by-step explanation:

Midpoint formula is X1 plus X2, then divided by 2. So, because the midpoint is given you work backwards. So for the x value do (-3 + x) divided by 2 equals -2 and solve for x and you do the same thing for the Y value

8 0
3 years ago
What is not a composite number out of 2 4 6 8
sattari [20]

Answer:

2

Step-by-step explanation:

2 has the factors 2 and 1 while the others have:

4- 4, 2,1

6- 6, 3, 2, 1

8- 8, 4, 2, 1

3 0
3 years ago
The area of the rhombus is 540 cm2; the length of one of its diagonals is 4.5 dm. What is the distance between the point of inte
malfutka [58]

1. The area of the rhombus can be found by the formula

A=\dfrac{d_1\cdot d_2}{2}, where d_1,\ d_2 are rhombus's diagonals.

Note that d_1=4.5\ dm=45\ cm, then

540=\dfrac{45\cdot d_2}{2},\\ \\540\cdot 2=45d_2,\\ \\d_2=24\ cm.

2. The diagonals of rhombus are perpendicular and are bisectors of each other. Then the triangle formed with halfs of diagonals is right triangles with legs

\dfrac{d_1}{2}=22.5\ cm,\ \dfrac{d_2}{2}=12\ cm.

The hypotenuse of this triangle is the rhombus's side. By the Pythagorean theorem

\text{rhombus's side}^2=(22.5)^2+12^2=506.25+144=650.25,\\ \\\text{rhombus's side}=25.5\ cm.

3. The distance between the point of intersection of the diagonals and the side of the rhombus is the height of right triangle considered above.

Use twice the Pythagorean theorem to find this height:

\left\{\begin{array}{l}x^2+h^2=12^2\\(25.5-x)^2+h^2=22.5^2,\end{array}\right.

where x is projection of leg 12 cm and h is height.

Subtract the first equation from the second:

(25.5-x)^2+h^2-x^2-h^2=22.5^2-12^2,\\ \\650.25-51x=506.25-144,\\ \\51x=650.25-362.25=288,\\ \\x=\dfrac{96}{17}\ cm.

Then

h^2=144-\left(\dfrac{96}{17}\right)^2=144-\dfrac{9216}{289}=\dfrac{32400}{289},\\ \\h=\dfrac{180}{17}\ cm.

Answer: h=\dfrac{180}{17}\ cm.

7 0
3 years ago
Read 2 more answers
Pls help me guys this is my last question .
aleksandrvk [35]

Answer:

0

Step-by-step explanation:

x = 5

5 - 5 = 0

this should

be right

3 0
3 years ago
Read 2 more answers
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