The lines y=3x-1 and y=ax+2 are perpendicular if a=___
2 answers:
Answer:
Step-by-step explanation:
The equation of line in the form .
y = mx + c
Where m is the slope and c is the y- intercept .
As given
The lines y=3x-1 and y=ax+2 are perpendicular .
Here 3 is slope for equation of line y=3x-1 and a is slope for equation of line
y=ax+2 .
Now by using properties of the perpendicular lines property .
When two lines are perpendicular than slope of one line is negative reciprocal of the other line .
Thus
Therefore
To find the perpendicular slope, you find the reciprocal of the slope (in this case, 1/3) and multiply that by -1 (in this case, it gets -1/3)
You might be interested in
I'm pretty sure its A but it could be B
I have a good record of guessing the right one so I would say #1.
Answer:
Point B is
Step-by-step explanation:
X2+y2–x–2y–11/4=x2−x+14−14+y2−2y+4−4−11/4=(x−12)2+(y−2)2−14−4−114=(x−12)2+(y−2)2−7=0(x−12)2+(y−2)2=(7√)2
Center(1/2 ,2)
radius = \sqrt 7
When you evaluate the equation you plug in the numbers or replace the variables with the numbers it’s giving you.
