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3 years ago

5) Using the terms "input" and "output" and the definition of a function, explain why this relationship is or is

Mathematics

1 answer:

Aleks [24]3 years ago

6 0

Answer:

This relationship is a function

Step-by-step explanation:

While a function may not have two output values (y) assigned to the same input value (x), it may have two input values (x) assigned to the output value (y).

The table follows that rule

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Find the value of 21 + 4(32 - 5). <br> A- 25 <br> B- 37 <br> C- 100

Mashutka [201]

Answer:

Explanation:

21+4(3^2−5)

= 21+4(9−5)

= 21+(4)(4)

= 21+16

= 37

Mordancy.

7 0

3 years ago

Dave has 10 poker chips, 6 of which are red and the other 4 of which are white. Dave likes to stack his chips and flip them over

Marina86 [1]

The number of 10 chips stacks that Dave can make if two stacks are not considered distinct is 110.

The solution

To get the symmetric stacks, one has to subtract the symmetric stacks to know the ones that are asymmetric.

The symmetric are flipped. Given that they are double counted what we have to do is to divide through by 2.

6/2 = 3

10/2 = 5

4/2 = 2

1/2(10C6) - (5C3) + (5C3)

0.5(210-10+10)

= 110

8 0

2 years ago

0.008 is 1/10 of what decimal?

Bas_tet [7]

The answer is .1 or .10

6 0

3 years ago

Can someone help me please

rjkz [21]

Answer:

I'm gonna go with D

Step-by-step explanation:

If it's wrong meh bad

3 0

3 years ago

Read 2 more answers

A researcher works on a study that has a population standard deviation of 0.73a sample mean of 84.5 and a sample size of 60 .Wha

Firlakuza [10]

Answer:

$ME = z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

The critical value can be founded in the normal standard distribution table using the value of $\alpha/2 =0.025$ and we got $z_{\alpha/2}=1.96$ . Replacing the info given we got:

$ME = 1.96 \frac{0.73}{\sqrt{60}}= 0.185$

Step-by-step explanation:

For this case we have the following info given:

$\sigma = 0.73$ represent the population deviation

$\bar X = 84.5$ represent the sample mean

$n =60$ represent the sample size

And we want to find the margin of error for a confidence level of 95%. So then the significance level would be $\alpha=1-0.95 = 0.05$ and $\alpha/2 =0.025$ . The margin of error is given by:

$ME = z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

The critical value can be founded in the normal standard distribution table using the value of $\alpha/2 =0.025$ and we got $z_{\alpha/2}=1.96$ . Replacing the info given we got:

$ME = 1.96 \frac{0.73}{\sqrt{60}}= 0.185$

6 0

4 years ago