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g100num [7]
3 years ago
14

Pls help it timed!!!!

Mathematics
1 answer:
Studentka2010 [4]3 years ago
8 0

Answer:

its subtraction property of equality

Step-by-step explanation:

it shows that the 3/4 next to the 16 was subtracted on both sides to cancel out on of the other 3/4 on the other side...

i uploaded a pic just incase u didnt understand

Hope this helps!!!

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Help me plz well mark brainliest if correct!
qwelly [4]

Answer:

15

Step-by-step explanation:

To subtract 2 1/2 - 1 3/5, first, you need a common denominator for the fractions, which is 10.

The subtraction becomes

2 5/10 - 1 6/10

Now you need to subtract 1 6/10 from 2 5/10.

Since the fraction part involves the subtraction 5/10 - 6/10, we need to borrow. You must change 2 5/10 to a mixed numeral with a larger numerator than 5, so you can subtract 6/210 from it.

Start with 2 5/10.

Borrow 1 from the 2. The 1 you borrow from 2 will be added to 5/10.

You think of the borrowed 1 as 10/10. Now you add 10/10 to 5/10.

2 5/10 becomes 1 15/10. Now that the fraction has a numerator grater than 6, you can do the subtraction.

2 5/10 - 1 6/10 =

= 1 15/10 - 1 6/10

Answer: 15

3 0
3 years ago
Read 2 more answers
3 sponges cost $3.90. What is the unit price?
Leokris [45]

Answer:

To find the unit price, we divide the total cost by the number of items.

$3.90 ÷ 3 = $1.30

That means the unit price is $1.30 for each sponge.

7 0
3 years ago
Read 2 more answers
What is the unit rate of a 1.25L Coca Cola that cost $1.29
Artyom0805 [142]

a 1.25L Coca Cola that cost $1.29

Unit rate means we need to find the rate of 1 liter of Coca Cola

1.25 L Coca Cola =  $1.29

1 L of Coca Cola = ?

To find 1 liter of Coca cola divide the cost by liter, so we divide 1.29 by 1.25

\frac{1.29}{1.25}

1.032

So the cost of 1 liter of Coco Cola = $1.032

5 0
3 years ago
Find the GCF of 207c^3 and 108c^2
geniusboy [140]

Answer:  9c²

<u>Step-by-step explanation:</u>

To find the Greatest Common Factor of 207c³ and 108c², first factor them down to their primes and see what they have in common.

                207c³                     108c²

                 ∧   ∧                        ∧  ∧

             9·23  c·c·c              9·12   c·c

            ∧                            ∧  ∧

           3·3                         3·3 3·4

                                                  ∧

                                                 2·2

                   

207c³: 3·3·23  c·c·c

108c²:  2·2·3·3·3·4 c·c

GCF = 3·3 c·c

        = 9c²

7 0
4 years ago
the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years​
Yuliya22 [10]

Answer:  125 g

<u>Step-by-step explanation:</u>

A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k

\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125

8 0
4 years ago
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