1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vladimir1956 [14]
3 years ago
9

I’ll brainliest you please help me

Mathematics
1 answer:
elixir [45]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Using the pythagorean theorem, we can determine if these are right triangles or not.

equation: sqrt a^2+b^2=c

this means the square root of the two shortest sides squared must equal to the largest side, (the hypotenuese).

Work for C:

Squareroot of 32^2 + 24^2 = 40cm

You might be interested in
Match the y-coordinates with their corresponding pairs of x-coordinates on the unit circle. the x coordinates to choose from are
vaieri [72.5K]
Of the four x-coordinates to choose only 1/√(11) belongs can belong to the unit circle.

The other three x-coordinates are greater than 1, then they are out of the unit circle.

The unit circle formula is x^2 +y^2 = 1

Then to find the y-coordinate given the x-coordinate you can solve for y from that formula:

y^2 = 1 - x^2

y = (+/-)√(1-x^2)

Substitute the value of x

y = (+/-)√{1 - [1/√(11)]^2} = (+/-) √{(1 - 1/11} =(+/-) √ {(11 -1)/11 =(+/-)√(10/11) ≈ +/- 0.95


6 0
3 years ago
a right rectangular prism has a length of 2 1/2 feet and width of 3 feet and a height of 1 and 1/2 feet. Unit cubes with side le
anygoal [31]
The volume of the right rectangular prism is the product of all its dimensions, length, width and height. Since all these dimensions are given, therefore, we can directly calculate the volume of the right rectangular prism by substitution to the formula.

V = L*W*H
V = (2.5 ft)(3 ft)(1.5 ft)
<em>V = 3.375 ft³ or 3 and 3/8 ft³</em>
7 0
4 years ago
Read 2 more answers
Solve the quadratic equation<br> HINT: Answers will be a decimals<br> 2x2 - 12x+8 = 3
Oduvanchick [21]

Answer:

x= 5.55 and 0.45

Step-by-step explanation:

Quadratic Equation = (-b±√b²-4(a)(c))÷2(a)

Get equation = to 0 by subtracting the 3 on the right side of the = sign

2x² - 12x + 5

Identify the variables

a=2

b=-12

c=5

Put them into the quadratic equation

(-(-12)± √-12² - 4(2)(5))÷2(2)

Simplify

(12 ±√144 - 40)÷4

(12±√104)÷4

Now split into 2 equations (one with addition one with subtraction) because of the ± then continue simplifying

(12 - √104)÷4                  (12 + √104)÷4

(12 - 10.198039)/4          (12 + 10.198039)/4

5.54950975                  0.45049025

Round

5.55                               0.45

6 0
3 years ago
What is the weight (in grams) of a liquid that exactly fills a 163.5 milliliter container if the density of the liquid is 0.492g
kolezko [41]

m = ρ v

m = (0.492 g / mL) * 163.5 mL

m = 80.442 g

rounded to nearest hundredth:

m = 80.44 g

8 0
4 years ago
Read 2 more answers
The line plots shows the distance, in miles, that students walked on Friday. How many students walked over 1/2 of a mile.
otez555 [7]
U count how many students were walking then multiply it by half itself
3 0
3 years ago
Other questions:
  • For which value of x must the expression radical 71x be further simplified?
    8·1 answer
  • Solve the equation by completing the square.<br><br> 3x^2 -6+9=0
    5·2 answers
  • In polar coordinates the positive x axis is called?
    11·2 answers
  • Does anyone know the answer <br> 10 points
    12·2 answers
  • Multiply using an area model or the distributive property. "So my question is how do I put this."
    11·1 answer
  • Which order pair represents the solution to the system of linear equations?
    10·2 answers
  • On a given planet, the weight of an object varies directly with the mass of the object. Suppose that an object whose mass is 4kg
    14·1 answer
  • (4.9 - 3.125) divided by 5 someone help :)
    11·1 answer
  • Help please, asap!!! Please show work!
    6·1 answer
  • X*[y+(-6)]=[13*(-19)]+[13*z]
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!