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2 years ago

Solve the quadratic equation HINT: Answers will be a decimals 2x2 - 12x+8 = 3

Mathematics

1 answer:

Oduvanchick [21]2 years ago

6 0

Answer:

x= 5.55 and 0.45

Step-by-step explanation:

Quadratic Equation = (-b±√b²-4(a)(c))÷2(a)

Get equation = to 0 by subtracting the 3 on the right side of the = sign

2x² - 12x + 5

Identify the variables

a=2

b=-12

c=5

Put them into the quadratic equation

(-(-12)± √-12² - 4(2)(5))÷2(2)

Simplify

(12 ±√144 - 40)÷4

(12±√104)÷4

Now split into 2 equations (one with addition one with subtraction) because of the ± then continue simplifying

(12 - √104)÷4 (12 + √104)÷4

(12 - 10.198039)/4 (12 + 10.198039)/4

5.54950975 0.45049025

Round

5.55 0.45

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A car travels 2 5/8 miles in 3 1/2minutes at a constant speed. Which equation represents the distance, d, that the car travels i

kakasveta [241]

Answer:

Step-by-step explanation:

2⅝ miles/(3½ minutes) = (21/8 miles)/(7/2 minutes) = ¾ mile/minute

d = ¾m = 0.75m

8 0

2 years ago

F(x) =5x^2-20x+3 how to find minimum

Leya [2.2K]

Answer:

(2,-17) should be the minimum.

Step-by-step explanation:

The minimum of a quadratic function occurs at $x=-\frac{b}{2a}$ . If a is positive, the minimum value of the function is $f(-\frac{b}{2a})$

$f_{min}x=ax^2+bx+c$ occurs at $x=-\frac{b}{2a}$

Find the value of $x=-\frac{b}{2a}$

x = 2

evaluate f(2).

replace the variable x with 2 in the expression.

$f(2)=5(2)^2-20(2)+3$

simplify the result.

$f(2)=5(4)-20(2)+3$

$f(2)=20-40+3$

$f(2)=-17$

The final answer is -17

Use the x and y values to find where the minimum occurs.

HOPE THIS HELPS!

3 0

2 years ago

assume the situation can be exposed as a linear cost, find the cost function, fixed cost is $100, 40 items cost 1,200 to produce

alexira [117]

C(x) = 1200(40) + 100
or
= mx+c
where m = 1200, x = 40, y = 100

hope it helped,
click thx if it did.

7 0

2 years ago

A bulletin board has a perimeter of 200 inches. Which expression expresses the area A(w) of the bulletin board as a function of

mr Goodwill [35]

Answer:

area A(w) of the bulletin board as a function of its width, w =[100-w]*w= 100w- $w^{2}$

Step-by-step explanation:

let, the shape of the bulletin board is a rectangle,

then the perimeter of it = sum of all sides

= 2[length+width] = 2[l+w]

(let l: length, w : width )

so, 200 = 2[l+w]

100= l+w ( dividing both the sides by 2)

so, l= 100-w

area = length*width=l*w=[100-w]*w

therefore,area A(w) of the bulletin board as a function of its width, w =[100-w]*w= 100w- $w^{2}$

6 0

2 years ago

Please help, I need an explanation because I'm confused on how to do this.

gladu [14]

Answer:

15°

Step-by-step explanation:

If CB is a diameter, the arc BKAC is a semicircle and has a degree measure of 180. If the measure of angle BCK is 20 and it is an inscribed angle, then the measure of the arc it intercepts is twice that. So arc BK measures 40 degrees. That means that arc KA has a measure that is found by subtracting arc AC and arc BK from 180. 180 - 40 - 110 = 30. If that arc is 30 and the angle that intercepts it is inscribed, then the angle measure is half the measure of the arc. So the angle is 15°

3 0

3 years ago