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son4ous [18]
3 years ago
7

Luis cortó

Mathematics
1 answer:
Igoryamba3 years ago
5 0

Answer:

El resto de la cuerda tiene una longitud de 41.5 pulgadas.

Step-by-step explanation:

Luis corta una porción de la cuerda y la lleva consigo. El remanente es aquella porción de la cuerda que no es llevada por Luis. Si sabemos que la cuerda tiene una longitud total de 60 pulgadas y que Luis se lleva 18\,\frac{1}{2} pulgadas, entonces la porción remanente se obtiene con la siguiente sustracción:

x = 60\,in -\left(18\,in + \frac{1}{2}\,in \right)

x = 60\, in - \frac{37}{2}\,in

x = \frac{83}{2}\,in

x = 41.5\,in

El resto de la cuerda tiene una longitud de 41.5 pulgadas.

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Answer:

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Step-by-step explanation:

A graphing calculator provides a nice answer for these questions. It shows the maximum height is 48.6 feet, and the time in air is 3.4 seconds.

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The equation can be rewritten to vertex form to find the maximum height.

  h(t) = -16(t^2 -54/16t) +3 . . . . . group t-terms

  h(t) = -16(t^2 -54/16t +(27/16)^2) + 3 + 27^2/16

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The maximum height is 48 9/16 feet, about 48.6 feet.

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The air time is found at the value of t that makes h(t) = 0.

  0 = -16(t -27/16)^2 +48 9/16

  (-48 9/16)/(-16) = (t -27/16)^2 . . . . . . . subtract 48 9/16 and divide by -16

  (√777 +27)/16 = t ≈ 3.4297 . . . . . square root and add 27/16

The time in air is about 3.4 seconds.

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See attached screen capture with the point highlighted

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Step-by-step explanation:

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