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liq [111]
3 years ago
11

The estimated populations of two different countries in 2030 are shown in the table. What is the difference between the estimate

d population of countries A and the estimated population of country B in 2030 written in scientific notation.
country A: 1,300,000,000
Country B: 144,000,000​
Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0

Answer: A (1.156x10(6)

Step-by-step explanation: IM DOING THE INTERIM TOOOOOO

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-4 = x -1 can I see you work it out please?
kherson [118]
We need to get x alone, to do that we add 1 to both sides to cancel out the -1 on the right.
-4 = x -1
+1 +1
-3=x

This means x is equal to -3. Hope this helps!
4 0
3 years ago
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Venla is 5 years older than her cousin Kora. How old is Kora when Venla is 18 years old?
krek1111 [17]

Answer:

kora is 13

Step-by-step explanation:

venla is 5 years older than kora

18-5=13

5 0
3 years ago
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Write an equation in standard form using integers <br><br> Y= - x<br> —<br> 5
kykrilka [37]

Answer:

x + y = - 5

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y = - x - 5 ( add x to both sides )

x + y = - 5 ← in standard form

8 0
3 years ago
Which formula best expresses your monthly ending balance?
igor_vitrenko [27]
Withdrawals must be subtracted from the beginning balance since to withdraw means to take out, so withdrawing money would lower the balance.
Deposits are added to the balance, so they must be added in the equation.

The answer is <span>c) Beginning Balance - Withdrawals + Deposits = Ending Balance</span>
4 0
3 years ago
3-2i/1+4i include each step necessary in simplifying
Likurg_2 [28]

Answer:

\frac{3-2i}{1+4i}=\frac{11}{17}-\frac{10}{17}i

Step-by-step explanation:

\frac{3-2i}{1+4i} <-- Given

\frac{3-2i}{1+4i}*\frac{1-4i}{1-4i} <-- Multiply by the conjugate of the denominator as a factor of 1

\frac{(3-2i)(1-4i)}{(1+4i)(1-4i)}

\frac{(3)(1)+3(-4i)-2i(1)-2i(4i)}{(1)(1)+1(-4i)+4i(1)+4i(-4i)} <-- Use the Distributive Property and FOIL

\frac{3-12i-2i-8i^2}{1-4i+4i-16i^2}

\frac{3-10i-8i^2}{1-16i^2}

\frac{3-10i-8(-1)}{1-16(-1)} <-- Rewrite i^2 as -1

\frac{3-10i+8}{1+16}

\frac{11-10i}{17}

\frac{11}{17}-\frac{10}{17}i <-- Rewrite in a\pm bi form

8 0
3 years ago
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