The answer for your question is 4.166666667 thank you for letting me answer your question and you welcome now bye have a great day.
Its fairly straightforward. Since the bottom equation only has one unknown,x, because y=1.3, you can plug y in and solve for x. Once you find the value of x, you then have the value for two variables, x and y, and again have one unknown coefficient a. To solve for the coefficient you just plug in your y value (1.3) and your x value (which can be rounded to 0.42). Using a little bit of algebra, you can then solve for a which should be a=2.108. I am not sure if your teacher wants you to solve it this way but you could also use the elimination method or substitution method that you would of learned when discussing system of equations. But no matter which way you do it, the math follows the rules. Hope this helps. I’d suggest you solve it yourself to double check my work.
To verify my credibility,
I am a Mechanical Engineering major w/ minor in mathematics
Answer:
I think 6.............,..........
Y = x - 9 meets the y-axis at (0,-9)
y = -2x - 3 meets the y-axis at (0,-3)
This is because for every linear equation, there is a formula corresponding to it as y=mx + c, where (0,c) is where it meets the y-axis. As we assign the value of 0 to x, only c will be left to equal y, being the intercept.
So the first hour it travels from 1-6 miles, the second hour it travels at least two miles. And the question is "draw the range of miles the boat could of traveled in the second hour". Well first of all the third hour is completely useless so forget about that. Now, the first hour says it traveled from 1-6 miles, we don't know how many miles it traveled for sure but it could of traveled up to 6. So in the second hour when they say "at least two miles" the boat could of travled at least two miles more than 1-6. So 1+2+3, 2+2+4, 3+2=5, 4+2=6, 5+2=7 and 6+2=8. So the boat could of traveled from 3 to 8 miles in the second hour.
