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1 answer:
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Answer:
For this case we have this function given:
In order to find the domain we need to find the possible values of x that the function can assume.
And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:
And we can write this in formal notation as:
And the best answer for this case would be:
all real numbers greater than 0
Step-by-step explanation:
For this case we have this function given:
In order to find the domain we need to find the possible values of x that the function can assume.
And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:
And we can write this in formal notation as:
And the best answer for this case would be:
all real numbers greater than 0
Answer:
Step-by-step explanation:
In the equation, 72t represents the initial upwards velocity and 5 represents the initial launching height. The leading term represents the pull of gravity on the object in the English system of measurement.
So the first question says the initial height is 5 feet. TRUE
The second question says the initial vertical velocity is -72. FALSE (it's positive 72 ft/sec)
The third question says that the object will hit the ground after approximately 4.57 seconds. TRUE. Find this by setting the h(t) on the left equal to 0, since this is the height at any time during the flight. When h(t) = 0, that means that there is NO height, which means the object is on the ground. Set the equation equal to 0 and factor to find t. Putting that into the quadratic formula gives you t values of -.068 and 4.57. Since the 2 things in math that will NEVER EVER be negative are distances and time, we can safely disregard the negative t value and go with t = 4.57.
The fourth question says that after t = 3 seconds, the object is 173 feet high. FALSE. Find this by subbing in a 3 for every t in the equation.
This gives you that h(3) = 77 feet
The last question says that at t = 0, h(t) = 0. FALSE again. Sub in a 0 for every t in the equation, and you get h(0) = 5, which is the initial launching height.