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Alja [10]
3 years ago
7

I do all things in zero sums in my head is that possible to be a zero?

Mathematics
2 answers:
elixir [45]3 years ago
6 0
Yes but it dose depend on the problem
aev [14]3 years ago
4 0
Ya it depends on the problem
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Julie goes shopping complete the following table to show his shopping bill
Murrr4er [49]

Answer:

£75.53

Step-by-step explanation:

3tshirt=£17.82

2pauntbrush=£13.94

4bags of pasta=£3.52

toral=£17.82+£13.94+£3.52+£41.25=75.53

4 0
2 years ago
Will give brainliest.
dolphi86 [110]

Answer:

Its a right isosceles triangle

4 0
2 years ago
Read 2 more answers
Two numbers, a and b, are stored in one byte floating point notation using the least significant (rightmost) 3 bits for the expo
ehidna [41]

a=00110111 = 00110_2 \times 2^{111_2} = 6 \times 2^{-1} = 3


b=11011000 =  11011_2 \times 2^{000_2} = -(0100_2 + 1) =-(4+1)=-5


a+b=-2 = -1 \times 2^{001} = -2 \times 2^{0} = -4 \times 2^{-1} etc.


a+b=-2 = 11111001 = 11110000 = 11100111 = ...


Hard to select the correct answers without seeing the choices. Let's check a couple,


11111001 = -(00000+1) \times 2^{1} = -2 \quad\checkmark


11110000 = -(00001 + 1) \times 2^{0} = -2 \quad\checkmark


11100111 = -(00011 + 1) \times 2^{-1} = -4/2= -2 \quad\checkmark


4 0
3 years ago
There are only green pens and red pens in a box. there are 3 more red pens than green pens in the box. sheila is going to take a
e-lub [12.9K]

Answer: 6 or 9

Step-by-step explanation:

Given the following :

Let the number of green pens = x

Number of red pens = x + 3

Probability of picking same color = 17/35

Taking two pens at random; probability of picking two pens of same color.

Probability of picking red on first pick then red on second pick ; or picking blue on first pick then blue on second pick

Probability = (Required outcome / Total possible outcomes)

Total number of pens = x + x + 3 = 2x + 3

Probability of picking red then red:

P(red first) = (x+3)/2x+3

P(red second) = x+3-1 / 2x+3-1 = (x+2)/2x+2)

Therefore, probability of red then red =

(x+3)/(2x+3) × (x+2)/2x+2)

= (x+3)(x+2) / (2x+3)(2x+2)

Probability of green then green:

P(first green) = x/(2x+3)

P(second green) = (x-1) / (2x+3-1) = (x-1) / (2x+2)

P(green then green) = x(x-1)/(2x+3)(2x+2)

Therefore,

[(x+3)(x+2) / (2x+3)(2x+2)] + [x(x-1)/(2x+3)(2x+2)] = 17/35

(x+3)(x+2)+x(x-1) / (2x+3)(2x+2) = 17/35

Cross multiply :

35(x+3)(x+2)+x(x-1) = 17(2x+3)(2x+2)

35(2x^2 + 4x + 6) = 17(4x^2 + 10x + 6)

70x^2 + 140x + 210 = 68x^2 + 170x + 102

70x^2 - 68x^2 + 140x - 170x + 210 - 102 = 0

2x^2 - 30x + 108 = 0

Now we have a quadratic equation which can be factoeized used using any known factorization method.

Factorizing this, we get

(x-6) = 0 or (x-9) = 0

x = 6 or x = 9

6 0
3 years ago
4=-8p-7+9p find the solution to the equation or inequality?
andrey2020 [161]
Subtract 8p from 9p and then rewrite the equation. Then you add 7 to 4 and rewrite the equation again. Then you divide 1p by 11 and get p=11.
6 0
3 years ago
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